Help me please. i will mark brainliest ‼️

Mathematics

1 answer:

Alik [6]3 years ago

8 0

Answer:

can i have a thxs because this question has been here for a week plz

Step-by-step explanation:

You might be interested in

Do one of the following, as appropriate. (a) Find the critical value z Subscript alpha divided by 2, (b) find the critical v

aliya0001 [1]

Answer:

$t=\pm 2.95$

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The t distribution or Student’s t-distribution is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.

Data given

Confidence =0.99 or 99%

$\alpha=1-0.99=0.01$ represent the significance level

n =16 represent the sample size

We don't know the population deviation $\sigma$

Solution for the problem

For this case since we don't know the population deviation and our sample size is <30 we can't use the normal distribution. We neeed to use on this case the t distribution, first we need to calculate the degrees of freedom given by:

$df=n-1=16-1=15$

We know that $\alpha=0.01$ so then $\alpha/2=0.005$ and we can find on the t distribution with 15 degrees of freedom a value that accumulates 0.005 of the area on the left tail. We can use the following excel code to find it:

"=T.INV(0.005;15)" and we got $t_{\alpha/2}=-2.95$ on this case since the distribution is symmetric we know that the other critical value is $t_{\alpha/2}=2.95$

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5C%7B%20%5Cfrac%20%7B%20%28%20%5Csqrt%20%7B%203%20%7D%20%29%20%5Ctimes%203%20%5E%20%7B%20-%20

ZanzabumX [31]

Answer:

Step-by-step explanation:

Exponent law:

$\sf \bf a^m * a^n = a^{m+n}\\\\ (a^m)^n = a^{m*n}$

$\sf a^{-m}=\dfrac{1}{a^m}$

First convert radical form to exponent form and then apply exponent law.

$\sf \sqrt{3}=3^{\frac{1}{2}}\\\\\sqrt{5}=5^{\frac{1}{2}}$

$\sf \left(\dfrac{(\sqrt{3}*3^{-2}}{(\sqrt{5})^2}\right)^{\frac{1}{2}}= \left(\dfrac{3^{\frac{1}{2}}*3^{-2}}{(5^{\frac{1}{2}})^2} \right )^{\frac{1}{2}}$

$= \left(\dfrac{3^{\frac{1}{2}-2}}{5^{\frac{1}{2}*2}}\right)^{\frac{1}{2}}\\\\=\left(\dfrac{3^{\frac{1-4}{2}}}{5}\right)^{\frac{1}{2}}\\\\=\left(\dfrac{3^{\frac{-3}{2}}}{5}\right)^{\frac{1}{2}}\\\\=\dfrac{3^{\frac{-3}{2}*{\frac{1}{2}}}}{5^{\frac{1}{2}}}\\\\ =\dfrac{3^{{\frac{-3}{4}}}}{5^{\frac{1}{2}}}$