So you make them the same common denominator
As you see, 2/10 = 8/40
2/4 = x/40, multiply by 10
2/4 = 20/40
Then add because same denominator
Now you would get:
8/40 + 20/40 = 28/40
If it is not intersect they are not parallel
Answer:
The answer is D
Step-by-step explanation:
the y is +10
slope is -1/3
Answer:
6.14125(0.15) = 0.9211875 (below 1)
6.14125 - 0.92118 = 5.22007
Step-by-step explanation:
Given data
1. 10(.15)=1.5
2. 10-1.5=8.5
3. 8.5 (.15)=1.275
4. 8.5-1.275=7.225
continuation the sequence
5) 7.225 (0.15) = 1.08375
6) 7.225 - 1.08375 = 6.14125
7) <u> 6.14125(0.15) = 0.9211875 (below -one)</u>
8 ) <u> 6.14125 - 0.9211875 = 5.2200625 (get number 5)</u>
9) 5.2200625(0.15) = 0.783009
10) 5.2200625 - 0.783009 = 4.4370532
Answer:
Quadrilateral ABCD is not a square. The product of slopes of its diagonals is not -1.
Step-by-step explanation:
Point A is (-4,6)
Point B is (-12,-12)
Point C is (6,-18)
Point D is (13,-1)
Given that the diagonals of a square are perpendicular to each other;
We know that the product of slopes of two perpendicular lines is -1.
So, slope(m) of AC × slope(m) of BD should be equal to -1.
Slope of AC = (Change in y-axis) ÷ (Change in x-axis) = (-18 - 6) ÷ (6 - -4) = -24/10 = -2.4
Slope of BD = (Change in y-axis) ÷ (Change in x-axis) = (-1 - -12) ÷ (13 - -12) = 11/25 = 0.44
The product of slope of AC and slope of BD = -2.4 × 0.44 = -1.056
Since the product of slope of AC and slope of BD is not -1 hence AC is not perpendicular to BD thus quadrilateral ABCD is not a square.
