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Alja [10]
2 years ago
14

Find the equation of the quadratic function with vertex (-2,18) passing through (-5,0)?

Mathematics
1 answer:
Sliva [168]2 years ago
7 0

Answer:

y-18=-2(x+2)^2

Step-by-step explanation:

Equation of the Quadratic Function

The vertex form of the quadratic function has the following equation:

y-k=a(x-h)^2

Where (h, k) is the vertex of the parabola that results when plotting the function, and a is a coefficient different from zero.

It's been given the vertex of the parabola as (-2,18):

y-18=a(x+2)^2

Now substitute the point (-5,0) and find the value of a:

0-18=a(-5+2)^2

Operating:

-18=a(-3)^2

-18=9a

Solving for a:

a = -18 / 9

a = -2

Thus, the equation of the quadratic function is:

\mathbf{y-18=-2(x+2)^2}

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The distance between the two points on the number line is of \mathbf{\frac{5}{9}} units.

-------------------------------------------

  • The distance between two numbers on the number line is given by the <u>subtraction of the greater by the smaller number.</u>
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-\frac{2}{9} - (-\frac{7}{9}) = -\frac{2}{9} + \frac{7}{9} = \frac{-2 + 7}{9} = \frac{5}{9}

Thus, distance of \mathbf{\frac{5}{9}} units.

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