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2 years ago

11

Which of the following data sets has the mean, median, mode, and range as the same number?

1 answer:

I am Lyosha [343]2 years ago

5 0

Answer:

A.

Step-by-step explanation:

6, 11,14,14,19,20

Adding these 6 numbers we get 84.

84 / 6 = 14 = mean.

Median = middle number(s) = 14

Mode = number occurring most = 14.

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See attached picture.

Andrei [34K]

Answer:

28

Step-by-step explanation:

Since the triangle is a right triangle, we can use SOH CAH TOA to find ?. 10 is OPPOSITE to ? and 21 is HYPOTENUSE to ?, so we can use SIN to find ?.

SIN(?) = 10/21

? = ARCSIN(10/21)

? = 28.437

5 0

2 years ago

Match each series with the equivalent series written in sigma notation

PIT_PIT [208]

Answer:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

$3 + 12 + 48 + 192 + 768$

The expression can be written as:

$3 \to 3*4^{0$ --- 0

$12 \to 3 * 4^{1$ ---- 1

$48 \to 3 * 4^{2$ --- 2

$192 \to 3 * 4^{3$ ---- 3

$768 \to 3 * 4^{4$ ---- 4

For the nth term, the expression is:

$Term = 3 * 4^{n$ ---- n

So, the summation is:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

Solving (b):

$4 + 32 + 256 + 2048 + 16384$

The expression can be written as:

$4 \to 4 * 8^0$ --- 0

$32 \to 4 * 8^1$ ---- 1

$256 \to 4 * 8^2$ --- 2

$2048 \to 4 * 8^3$ ---- 3

$16384 \to 4 * 8^4$ ---- 4

For the nth term, the expression is:

$Term \to 4 * 8^n$ ---- n

So, the summation is:

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

Solving (c):

$2 + 6 + 18 + 54 + 162$

The expression can be written as:

$2 \to 2 * 3^0$ --- 0

$6 \to 2 * 3^1$ ---- 1

$18 \to 2 * 3^2$ --- 2

$54 \to 2 * 3^3$ ---- 3

$162 \to 2 * 3^4$ ---- 4

For the nth term, the expression is:

$Term \to 2 * 3^n$ ---- n

So, the summation is:

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

Solving (d):

$3 + 15 + 75 + 375 + 1875$

The expression can be written as:

$3 \to 3 * 5^0$ --- 0

$15 \to 3 * 5^1$ ---- 1

$75 \to 3 * 5^2$ --- 2

$375 \to 3 * 5^3$ ---- 3

$1875 \to 3 * 5^4$ ---- 4

For the nth term, the expression is:

$Term \to 3 * 5^n$ ---- n

So, the summation is:

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

5 0

3 years ago

viktelen [127]

4) The first and second terms for both ratios need to be in the same order.

Step-by-step explanation:

Given ratio is:

16:36

In order to find any ratio equivalent to given ratio, the ratio can be divided by a number or multiplied to a number.

The equivalent ratio that is given: 72:32

If we multiply the given ratio by 2: We get 32:72

So,

Looking at the options we can conclude that the right answer is

4) The first and second terms for both ratios need to be in the same order.

Keywords: Ratio, Fractions

Learn more about ratios at:

#LearnwithBrainly

3 0

3 years ago

Suppose the researcher conducts a survey of a random sample of 25 students at her university and five of them say they want to a

storchak [24]

نيبتيززيت يهيهتيتيتيت يتيتيتتيتيتي يتيتيتتيت

7 0

3 years ago

Write and solve an equation to represent the following situation: an electrician earns an hourly wage of $13.50 plus a $75 bonus

Bingel [31]

149.25=13.5h+75
(149.25-75)/13.5=5.5=h

8 0

3 years ago