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larisa86 [58]
3 years ago
14

ANYONE GOOD AT MATH? PLEASE PLEASE PLEASE SOMEONE HELP ME :(

Mathematics
1 answer:
Mumz [18]3 years ago
3 0

Answer:

The parent function is f(x)=a(x-h)^{2} +k

That Parabola's equation is f(x)=x^{2}

Step-by-step explanation:

I can't really explain much, but the top equation is a formula for <em>all </em>equations for a parabola. h and k are the x and y-values of the vertex. a is, well, a.

How did I find the equation of the parabola? Simple. Since the vertex is on the origin, h and k are 0. Also, because it intercepts (2,4) and (1,1), a=1.

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The Commutative property states that order does not matter. Multiplication and addition are commutative.

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Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.
o-na [289]

Answer: \text{Length of AG=}\frac{2\sqrt{63}}{3}

Explanation:  

Please follow the diagram in attachment.  

As we know median from vertex C to hypotenuse is CM  

\therefore CM=\frac{1}{2}AB

We are given length of CG=4  

Median divide by centroid 2:1  

CG:GM=2:1  

Where, CG=4

\therefore GM=2 ft

Length of CM=4+2= 6 ft  

\therefore CM=\frac{1}{2}AB\Rightarrow AB=12

In \triangle ABC, \angle C=90^0

Using trigonometry ratio identities  

AC=AB\sin 30^0\Rightarrow AC=6 ft

BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3} ft  

CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3} ft

In \triangle CAN, \angle C=90^0  

Using pythagoreous theorem  

AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}

Length of AG=2/3 AN

\text{Length of AG=}\frac{2\sqrt{63}}{3} ft


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Step-by-step explanation:

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Two numbers rolled can be added to get a sum. Find P(sum is even.)
azamat
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