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laiz [17]
1 year ago
5

What was the problem at kenya airways described in this case? what management, organization, and technology factors contributed

to this problem?
Mathematics
1 answer:
MatroZZZ [7]1 year ago
8 0

The management, organisation, and technology factors contributed to this problem are listed below.

<h3>What was the problem at Kenya Airways ?</h3>

The  problem in the airways was that corporation didn't know its customers, the airline hasn't been able to take use of its market opportunity in recent years.

Airways was unable to evaluate and keep track of its marketing efforts.

The technology factor that contributed were:

  • No reliable systems for tracking and accounting.
  • The technology used was neither accurate nor consistent.

The Organisation factors that contributed were

  • No communication between the organisation and the customers
  • No track record of the online campaigns and advertisement output
  • Customer Relations Needed to be improved.

The Management factors that contributed were

  • The management never gave reviews to the organisation about the failing system
  • The management even didn't take reviews from the customers and from the people working.

To know more about  problem at Kenya Airways

brainly.com/question/27974672

#SPJ1

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Sloan [31]

Triangle ABC is similar to triangle DEC, ∠B ≅ ∠E and 3DE = 2BC

<h3>What is transformation?</h3>

Transformation is the movement of a point from its initial location to a new location. Types of transformation are <em>rotation, reflection, translation and dilation.</em>

Dilation is the increase or decrease in the size of a figure by a scale factor.

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2 years ago
Seventy cards are numbered 1 through 70 , one number per card. One card is randomly selected from the deck. What is the probabil
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Answer:

Probability = \frac{2}{35}

Step-by-step explanation:

Given

Total = 70

First, we need to list the multiples of 5

M_5 = \{5,10,15,20,25,30,35,40,45,50,55,60,65,70\}

Then, multiples of 3M_3 = \{3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54,57,60,63,66,69\}

Next, is to list out the common elements in both

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n(M_3\ n\ M_5) = 4

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