Answer:
4.12
Step-by-step explanation:
A^2+b^2=c^2 so 8^2+b^2=9^2 so 64+b^2=81 so b^2=17 so b=4.12
Answer:
;hivpuvhyphbn;
Step-by-step explanation:
Answer:
-I₁ + I₂ + I₃ = 0
I₁ = I₂ + I₃
Step-by-step explanation:
The image of the circuit is obtained online and attached to the question.
The junction rule is essentially a law of conservation of current (charges). It applies to electrical circuits at steady state.
It explains that the for any given junction (node in an electrical circuit), the sum of current entering the junction is equal to the sum of current leaving the junction. That is, the net sum of current at any junction is zero.
Current entering a junction is assigned a positive sign and that leaving the junction is assigned a negative sign.
Σ I = 0
From the image of the circuit attached, I₁ is leaving the junction labelled number 1 and I₂ and I₃ are entering the junction.
Hence,
-I₁ + I₂ + I₃ = 0
I₁ = I₂ + I₃
Hope this Helps!!!
Which question to answer?
Answer:
The answer is "MS and QS".
Step-by-step explanation:
Given ΔMNQ is isosceles with base MQ, and NR and MQ bisect each other at S. we have to prove that ΔMNS ≅ ΔQNS.
As NR and MQ bisect each other at S
⇒ segments MS and SQ are therefore congruent by the definition of bisector i.e MS=SQ
In ΔMNS and ΔQNS
MN=QN (∵ MNQ is isosceles triangle)
∠NMS=∠NQS (∵ MNQ is isosceles triangle)
MS=SQ (Given)
By SAS rule, ΔMNS ≅ ΔQNS.
Hence, segments MS and SQ are therefore congruent by the definition of bisector.
The correct option is MS and QS