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Leya [2.2K]
2 years ago
8

PLEASE ANSWER ASAP!!!!!!!

Mathematics
1 answer:
tia_tia [17]2 years ago
4 0

The exact value of \dfrac{cos(tan^{-1}(-1))}{sin(cos^{-1}(-\frac{3}{\sqrt{2}})} would be root 2.

<h3>What is a function?</h3>

The function is a type of relation, or rule, that maps one input to specific single output.

Given;

\dfrac{cos(tan^{-1}(-1))}{sin(cos^{-1}(-\frac{3}{\sqrt{2}})}

We know that

The inverse tan(-1) = -π/4

cos(-π/4) = 1/√2

The inverse cos(√3/2) = π//6

sin(π/6) = 1/2

Then substitute

\dfrac{cos(tan^{-1}(-1))}{sin(cos^{-1}(-\frac{3}{\sqrt{2}})}\\\\

\dfrac{(1/\sqrt{2}) }{(1/2)} \\\\= \sqrt{2}

Learn more about function here:

brainly.com/question/2253924

#SPJ1

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