Answer:
secθ = - 2
Step-by-step explanation:
Using the identity
sec²θ = 1 + tan²θ
= 1 + (
)² = 1 + 3 = 4 ( take the square root of both sides )
secθ = ± 
= ± 2
Since secθ < 0 in the third quadrant , then
secθ = - 2
Answer:
y = -(x + 1)² + 4
Step-by-step explanation:
y = -x² − 2x + 3
First, factor the leading coefficient from the first two terms.
y = -(x² + 2x) + 3
Complete the square.
y = -(x² + 2x + 1 − 1) + 3
Simplify and factor.
y = -(x² + 2x + 1) + 1 + 3
y = -(x + 1)² + 4
The values which could be the slope of the line are numbers > 0.
<h3>Which values could be the slope of the line?</h3>
According to the task content, it follows that the given line originates from the lower left quadrant and continues through the upper right quadrant.
It therefore follows that the line is ascending from left to right in which case, the slope of the line is positive.
Hence, the possible values of the slope include the set of numbers greater than 0.
Read more on slope of lines;
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Hidden right triangle
28 feet tall (1 leg)
the piece that fell over is the hypotonuse
last leg is what we need to find
81-28=53
a²+b²=c²
a and b are legs and c is the hypotonuse
given
on leg is 28 and the hypotonuse is 53
th othe leg is b
28²+b²=53²
784+b²=2809
minus 784 from both sides
b²=2025
sqrt both sides
b=45
answer is 45ft
