The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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18 units squared multiply 6 times 3 to get this answer- 18u^2
Na bro i dont even know what’s that tbh
we know that
The formula of the surface area of the cone is equal to
where
SA is the surface area
r is the radius of the cone
l is the slant height
in this problem we have
Solve the formula for l
substitute the values
therefore
<u>the answer is</u>
The slant height is 
