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LekaFEV [45]
2 years ago
15

Calculate the volume of a cylinder of radius 5cm and height 14cm (take pie 22/7)

Mathematics
1 answer:
HACTEHA [7]2 years ago
4 0

Answer:

<em>Volume of a cylinder = 1,100cm³</em>

Step-by-step explanation:

<em>Volume</em><em> of</em><em> a</em><em> cylinder</em><em> </em><em>=</em><em> </em><em>πr²</em><em>h</em>

<em>Given</em>

<em>π </em><em>=</em><em> </em><em>2</em><em>2</em><em>/</em><em>7</em>

<em>r </em><em>=</em><em> </em><em>5</em><em>c</em><em>m</em>

<em>h </em><em>=</em><em> </em><em>1</em><em>4</em><em>c</em><em>m</em>

<em>Substitute</em><em> the</em><em> </em><em>given</em><em> </em><em>information</em><em> </em><em>in</em><em> the</em><em> </em><em>problem</em><em>.</em>

<em>Volume</em><em> of</em><em> a</em><em> cylinder</em><em> </em><em>=</em><em> </em><em>2</em><em>2</em><em>/</em><em>7</em><em> </em><em>×</em><em> </em><em>(</em><em>5</em><em>c</em><em>m</em><em>)</em><em>²</em><em> </em><em>×</em><em> </em><em>1</em><em>4</em><em>c</em><em>m</em>

<em>Volume</em><em> of</em><em> a</em><em> cylinder</em><em> </em><em>=</em><em> </em><em>2</em><em>2</em><em>/</em><em>7</em><em> </em><em>×</em><em> </em><em>2</em><em>5</em><em>c</em><em>m</em><em>²</em><em> </em><em>×</em><em> </em><em>1</em><em>4</em><em>c</em><em>m</em>

<em>Volume</em><em> of</em><em> a</em><em> </em><em>cylinder </em><em>=</em><em> </em><em>1</em><em>,</em><em>100c</em><em>m</em><em>³</em>

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OLEGan [10]
Depends on the fraction to determine your answer
4 0
3 years ago
The area of the conference table in Mr. Nathan’s office must be no more than 175 ft2. If the length of the table is 18 ft more t
valentina_108 [34]
The answer is  0 < x <span>≤ 7 
</span>
First, we know that width =  x
Which means that length = x +18

So, the possible equation for the Table's area is

X (X + 18)  ≤ 175

X^2 + 18x - 175  <span>≤ </span>0

Next, we need to calculate is by using complete square method
x^2 + 18x + 81 <span>≤ 175 + 81

(x + 9)^2 </span><span>≤ 256

|x + 9| </span><span>≤ sqrt(256)

|x + 9| </span><span>≤ +-16

-16 </span>≤ x + 9 <span>≤ 16

</span>-16 - 9 ≤ x <span>≤ 16 - 9

</span>-25 ≤ x <span>≤ 7

Since the width couldn't be negative, we can change -25 with 0,

so it become
</span> 0 < x ≤ 7 
7 0
3 years ago
I'll give brainliest to whoever answers and gets it correct :))))) wrong answers and links will be reported
levacccp [35]

Answer:

y = 3x + 2; y = -x + 4

Step-by-step explanation:

Slope intercept form is in y = mx + b, where m is the slope and b is the y-intercept. In the first image, 2 is the y-intercept and 3 is the slope, yielding the equation y = 3x + 2.

For the second, 4 is the y-intercept and -1 is the slope, so the answer to the second image is y = -x + 4.

3 0
2 years ago
Read 2 more answers
I bought a box of granola bars at the store that has a volume of 210 cubic centimeters
Naya [18.7K]

Answer:

a and c

Step-by-step explanation:

The volume (V) of a cuboid is

V = lwh ( l is length, w is width, h is height )

The volume is given as 210 cm³

Check each of the dimensions given to determine which give the correct volume

a

V = 15 × 2 × 7 = 210 ← correct volume

b

V = 14 × 3 × 7 = 294 ← incorrect volume

c

V = 7 × 3 × 10 = 210 ← correct volume

Hence a and c  could be the dimensions of the box


6 0
3 years ago
Read 2 more answers
Will give brainliest
pychu [463]

The equation of a hyperbola is  x^{2}/9 - y^{2}/4 = 1

What are the steps to Hyperbola equation ?

To find the equation of hyperbola, the following steps must be taken. You need to identify;

  • The coordinate of the center
  • The coordinate of the vertices
  • The coordinate of the foci

The general equation of a hyperbola can be expressed as

x^{2}/a^{2} - y^{2}/b^{2} = 1

From the graph, we have the following parameters

a = 3

a^{2} = 3^{2} = 9

b = 2

b^{2} = 2^{2} = 4

The equation of a hyperbola can be expressed as

x^{2}/9 - y^{2}/4 = 1

The vertices = V(+/-a,0) = (+/-3,0)

The center = C(0,0)

The focus = F(+/-C, 0)

Where C^{2} = a^{2}  + b^{2}

C = \sqrt{9 + 4}

C = \sqrt{13}

Focus = F(+/- \sqrt{13}, 0)

The general equation for asymptote = +/- b/a X

= +/-2/3X

Therefore, the equation of a hyperbola can be expressed as

x^{2}/9 - y^{2}/4 = 1

Learn more about hyperbola here: brainly.com/question/3405939

#SPJ1

6 0
1 year ago
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