All categories

2 years ago

PLEASE I REALLY NEED YOUR HELP!

Mathematics

1 answer:

Ivenika [448]2 years ago

7 0

Answer:

x = 28

m∠ACD = 68°

Step-by-step explanation:

∠BAE ≅∠DAC because they are vertical angles

∠ACD = 180 - 124 = 56°

to find 'x': 56 + 2x + (180 - 4x) = 180

236 - 2x = 180

-2x = -56

x = 28

m∠ACD = 180 - 4(28) = 180 - 112 = 68°

You might be interested in

The 14th term of an arithmetical progression is 15 and it's 9th term is 35 find the 15th term

AURORKA [14]

Answer:

the 15th term is 11

Step-by-step explanation:

common difference is= -4

first term is 67

4 0

2 years ago

Salid bought 35 feet of window trim at a hardware store. The trim cost $1.75 per foot, including sales tax. If salid paid with a

ch4aika [34]

To work this out, you have to figure out how much Salid paid. This equals $61.25 as you have to multiply the cost and how much he wanted. Next, you have to subtract this from $100. This equals $38.75 (answer)
I hope this helped!! :))

4 0

3 years ago

Which expression can be used to convert 80 US to Australian dollars?

musickatia [10]

Answer:

0.9668 USD

Step-by-step explanation:

1 USD=1.0343 AUD 1AUD=0.9668 USD.

6 0

1 year ago

Which expression is equivalent to (StartFraction 4 m n Over m Superscript negative 2 Baseline n Superscript 6 Baseline EndFracti

Gennadij [26K]

Question

Which expression is equivalent to $\frac{4mn}{m^{-2}n^6}$ . Assuming $m \neq 0; n\neq 0$

Answer:

$\frac{4m^3}{n^5}$

Step-by-step explanation:

Given

$\frac{4mn}{m^{-2}n^6}$

Required:

Simplify

To simplify this, we start by splitting each individual function

$\frac{4mn}{m^{-2}n^6} = \frac{4m}{m^{-2}} * \frac{n}{n^6}$

From laws of indices

$\frac{a^x}{a^y} = a^{x-y}$

SO, the above expression can also be expressed the same way

$\frac{4m}{m^{-2}} * \frac{n}{n^6} = 4m^{1-(-2)} * n^{1-6}$

$\frac{4m}{m^{-2}} * \frac{n}{n^6} = 4m^{1+2)} * n^{1-6}$

$\frac{4m}{m^{-2}} * \frac{n}{n^6} = 4m^{3} * n^{-5}$

From laws of indices,

$a^{-x} = \frac{1}{a^x}$

So,

$\frac{4m}{m^{-2}} * \frac{n}{n^6} = 4m^{3} * \frac{1}{n^5}$

$\frac{4m}{m^{-2}} * \frac{n}{n^6} = \frac{4m^3}{n^5}$

Hence, $\frac{4mn}{m^{-2}n^6}$ is equivalent to $\frac{4m^3}{n^5}$

5 0

3 years ago

Read 2 more answers

Select the favorable outcomes for rolling doubles.

QveST [7]

By doubles as outcome means the first and second outcome must be same.

The first option has outcome as 1. (1-1) (2-2) (3-3) (4-4) (5-5) (6-6).

In this we have first and second outcome as same, so we can say it satisfies our requirement and option first is the correct choice.

8 0

3 years ago

Read 2 more answers