Answer:
-5 ≤ n ≤ 3
Step-by-step explanation:
Firstly we solve the equation two at a time;
5n + 17 ≥ n - 3
5n - n ≥ -3 - 17
4n ≥ -20
n ≥ -5
-5 ≤ n
n - 3 ≥ -15 + 5n
n - 5n ≥ -15 + 3
-4n ≥ -12
-n ≥ -3
n ≤ 3
Therefore,
5n+17 ≥ n–3 ≥ –15+5n, becomes
-5 ≤ n ≤ 3
Answer:
[7-2x+5y-(x-y) -[5x+3y-7]
= 7-2x+5y-x+y-5x-3y+7
=7+7-2x-x-5x+5y+y-3y
=14-8x+3y
=-8x+3y+14
Step-by-step explanation:
p could be 5 and q could be 8 this is just my guess but i think its right
The percentage of tardiness among the 102 pupils is 2.94.
<h2>Calculation of the percentage</h2>
According to the query,
Course A: Total number of students = 102
Number of tardy students = 3
Percent of students tardy in course A = (number of tardy students/total
number of students) * 100
=(3/102)*100
= 2.941
≈2.94
In case of course B: Total number of students = 85 & tardy student = 5
So, the percent of tardy student = (5/85)*100 = 5.88 %
Therefore, it is concluded that the percentage of student tardiness in course A is 2.94.
Learn more about the percentage here:
brainly.com/question/92258
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