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BlackZzzverrR [31]
3 years ago
10

PLEASE I REALLY NEED YOUR HELP!

Mathematics
1 answer:
Ivenika [448]3 years ago
7 0

Answer:

x = 28

m∠ACD = 68°

Step-by-step explanation:

∠BAE ≅∠DAC because they are vertical angles

∠ACD = 180 - 124 = 56°

to find 'x':   56 + 2x + (180 - 4x) = 180

236 - 2x = 180

-2x = -56

x = 28

m∠ACD = 180 - 4(28)  =  180 - 112  =  68°

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Drag the tiles to the correct boxes to complete the pairs.
erastova [34]

Answer:

√8 ==> 2 units, 2 units

√7 ==> √5 units, √2 units

√5 ==> 1 unit, 2 units

3 ==> >2 units, √5 units

Step-by-step explanation:

To determine which pair of legs that matches a hypotenuse length to create a right triangle, recall the Pythagorean theorem, which holds that, for a right angle triangle, the square of the hypotenuse (c²) = the sum of the square of each leg length (a² + b²)

Using c² = a² + b², let's find the hypotenuse length for each given pairs of leg.

=>√5 units, √2 units

c² = (√5)² + (√2)²

c² = 5 + 2 = 7

c = √7

The hypothenuse length that matches √5 units, √2 units is √7

=>√3 units, 4 units

c² = (√3)² + (4)²

c² = 3 + 16 = 19

c = √19

This given pair of legs doesn't match any given hypotenuse length

=>2 units, √5 units

c² = (2)² + (√5)²

c² = 4 + 5 = 9

c = √9 = 3

legs 2 units, and √5 units matche hypotenuse length of 3

=>2 units, 2 units

c² = 2² + 2² = 4 + 4

c² = 8

c = √8

Legs 2 units, and 2 units matche hypotenuse length of √8

=> 1 unit, 2 units

c² = 1² + 2² = 1 + 4

c² = 5

c = √5

Leg lengths, 1 unit and 2 units match the hypotenuse length, √5

3 0
3 years ago
The length of a rectangle is 2 more than twice the width. The area of the
vlada-n [284]

Answer: w=5 , L= 2+2(5)=12

Step-by-step explanation:

L=2+2W

A= 60

LxW=60, now we will replace the L

(2+2W)(W)=60   we multiply

2w^2+2w=60

2w^2+2w-60=0  we divide by 2 the equation so we can work easier

w^2+w-30=0

find out w using the quadratic equation

we will get 2 solution,

w=5 and another solution is -6, which is not valid, as the side can not be negative

8 0
3 years ago
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KiRa [710]
\int \! 70 - 6 \csc(\theta) \cot(\theta) \ \mathrm{d}\theta = \int \! 70 - 6 \cdot \frac{1}{\sin(\theta)} \cdot \frac{\cos(\theta)}{\sin(\theta)} \ \mathrm{d}\theta = \int \! 70 \ \mathrm{d}\theta - \int \! \frac{6 \cos(\theta)}{\sin^2(\theta)} \ \mathrm{d}\theta = 70 \theta + \frac{6}{\sin(\theta)} + C, \ C \in \mathbb{R}.
8 0
4 years ago
Pls help and show workings
andreev551 [17]

Answer: x = 11

Step-by-step explanation:

same as the last question, set them as equal and solve. here's my work:

<em>5x - 1 = 4x + 10</em>

<em>5x - 1 (+ 1) = 4x + 10 (+ 1)</em>

<em>5x = 4x + 11</em>

<em>5x (- 4x) = 4x (- 4x) + 11</em>

x = 11

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3 years ago
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Your answer is $17.56.
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