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jenyasd209 [6]
3 years ago
15

Julio is paid 1.4 times his normal hourly rate for each hour he works over 30 hours in a week. Last week he worked 35 hours and

earned $436.60 , write and solve an equation to find Julio's normal hourly rates, r. Explain how you know that your answer is reasonable
Mathematics
1 answer:
Harman [31]3 years ago
3 0
<span>Julio is paid 1.4 times his normal hourly rate for every excess hour he works in a week.
last week he worked 35 hours and got 436.60 dollars.
We need to find an equation so we can be able to solve Julio’s earnings:
=> Let X be the value of Julio’s rate
=> 30 * X + 5 x 1.4x = 436.6
=> 30x + 7x = 436.6
=> 37x = 436.6
=> 37x / 37 = 436.6 / 37
=> x = 11.8
Thus the original rate of Julio is 11.8 dollars
=> 1.4 x 11.8 = 16.52 dollars, the rate of Julio with added rate
=> 30 x 11.8  + 5 x 16.52
=> 354 + 82.6
=> 436.6

</span>



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you don't list any expressions to choose from but

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{\bold{\red{\huge{\mathbb{QUESTION}}}}}

The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has length 2. What is the area of the shaded sector formed by obtuse angle WXY?

\bold{ \red{\star{\blue{GIVEN }}}}

RADIUS = 2

CHORD = 2

RADIUS --> XY , XZ , WX

( BEZ THEY TOUCH CIRCUMFERENCE OF THE CIRCLES AFTER STARTING FROM CENTRE OF THE CIRCLE)

\bold{\blue{\star{\red{TO \:  \: FIND}}}}

THE AREA OF THE SHADED SECTOR FORMED BY OBTUSE ANGLE WXY.

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AREA COVERED BY THE ANGLE IN A SEMI SPHERE

AREA = ANGLE   \: \: IN  \: \:  RADIAN  \times RADIUS

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Total Area Of The Semi Sphere:-

AREA =   \pi \times radius  \\  \\ AREA = \pi \times 2 = 2\pi

Area Under Unshaded Part .

Given a triangle with each side 2 units.

This proves that it's is a equilateral triangle which means it's all angles r of 60° or π/3 Radian

So AREA :-

AREA =  \frac{\pi}{3}  \times radius \\  \\ AREA =  \frac{\pi}{3}  \times 2 \\  \\ AREA =  \frac{2\pi}{3}

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5 0
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The large box weighs 3\frac{1}{3} times as the small box:

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