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3 years ago

7x + 2y + 5 - 5x + Oy - 1 Simplify expresson

Mathematics

1 answer:

frozen [14]3 years ago

3 0

Answer:

To do this you have to combine like terms. For example, 7x and -5x.

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HELP ME PLZZ I NEED HELP WITH THIS !!

dimaraw [331]

Answer:

The answer is D. 18 + (-7)

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3 years ago

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Answer with solution

adelina 88 [10]

In general, the scalar multiple of k times u, is this:

 $k\vec u = k(ux, uy)=(Kux,Kuy)$

So, here's how we find $3\vec v$

$3\vec v = 3 * (2,4) = (3*2,3*4) 

= (6,12)$

The answer is (6,12).

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2 years ago

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The function h is defined as follows.

JulsSmile [24]

Answer:

The equation you are given is a quadratic. The standard form of a quadratic is y = a(x-h)2 + k where (h,k) is the vertex of the graph, which is a parabola. Vertically moving the graph 4 units upward means that you are moving k +4 units.

y = a(x-h)2 + k standard form

y = 5x2 - 4 original equation

y = 5(x-0)2 - 4 re-written in standard form

h = 0 k = -4

Four (4) units up is k + 4--->-4 + 4 = 0.

Therefore, f(x) = 5x2 + 0--->f(x) = 5x2.

Step-by-step explanation:

hope this helps

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2 years ago

ANSWER ASAP!!!

mr_godi [17]

Answer:

Step-by-step explanation:

got it right on edjenuity

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2 years ago

Find the zeros of the polynomial function and state the multiplicity of each.

zheka24 [161]

$\bf f(x) = 4(x + 7)^2(x - 7)^3\implies 0 = 4(x + 7)^2(x - 7)^3
\\\\\\
0=(x+7)^2(x-7)^3\implies 
\begin{cases}
0=(x+7)^7\\
\qquad 0=(x+7)(x+7)\\
\qquad -7=x\\
\qquad -7=x\\
----------\\
0=(x-7)^3\\
\qquad 0=(x-7)(x-7)(x-7)\\
\qquad 7=x\\
\qquad 7=x\\
\qquad 7=x
\end{cases}$

the -7 is found there twice, so it has a multiplicity of 2
the +7 is there thrice, so it has multiplicity of 3

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3 years ago