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Andre45 [30]
3 years ago
15

4t + 2u2 - u3 ; t=2 u=1

Mathematics
1 answer:
melisa1 [442]3 years ago
3 0
9, I believe.
4(2)+2(1)^2-(1)^3 (^ just means to the power of "exponent")
8+2-1=9
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What is the solution to the system of equations shown below 2x-y+z=4 4x-2y+2z=8 -x+3y-z+=5
jok3333 [9.3K]

Answer:

Step-by-step explanation:

2x - y + z = 4

4x - 2y + 2z = 8

-x + 3y - z = 5

2x - y  + z = 4

-x + 3y - z = 5

x + 2y = 9

4x - 2y + 2z = 8

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8 0
2 years ago
The Quadratic Equation c² + 6c+ 8 = 0<br><br> Show work please
Bad White [126]
The formula for the quadratic formula is x (c in this case) = (-b(+/-)√(b²-4ac))/2a
This is used for an equation in standard quadratic form: ax² + bx + c = 0
1.) Put it in the correct form, if not already in it.
Ex. c² + 6c + 8 = 0
2.) Identify each part of the equation:
a = 1 (the leading coefficient), b = 6 (the coefficient in front of the second variable), c = 8
3.) Plug in each variable answer
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4.) Simplify
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c = (-6(+/-)√(36-32))/2
c = (-6(+/-)√(4))/2
c = (-6(+/-)2)/2
*Here, the equation splits in two. It becomes:
c = (-6+2)/2 AND c = (-6-2)/2
*Simplify again:
c = -4/2 AND c = -8/2
c = -2 AND c = -4
The answers c = -2 and c = -4 would solve the given equation.
Hope this helps! :)
6 0
3 years ago
Read 2 more answers
The coordinates of points A and L are negative 4 and 8, respectively. What is the coordinate of the midpoint between them?
olga nikolaevna [1]
The midpoints between 4 and 8 would be 6 because 4 5 6 7 8, the middle term is 6
6 0
3 years ago
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