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Andre45 [30]
3 years ago
15

4t + 2u2 - u3 ; t=2 u=1

Mathematics
1 answer:
melisa1 [442]3 years ago
3 0
9, I believe.
4(2)+2(1)^2-(1)^3 (^ just means to the power of "exponent")
8+2-1=9
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The answer is the second option given
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C

Step-by-step explanation:

The tosses before that were all by chance, the probability is still the same. Nothing changes.

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To walk to her friend's house, Cristal normally walks 63 yards north and 16 yards east as shown. How many
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Answer:

65 yd

Step-by-step explanation:

The image of this walking path of Cristal is missing, so i have attached it.

From the image attached, we can see that the path "x" is the hypotenuse path a the triangle.

Thus, we can use pythagoras theorem to find the area. Thus;

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A computer system uses passwords that are six characters, and each character is one of the 26 letters (a–z) or 10 integers (0–9)
Blababa [14]

First of all, since we have 36 characters available per spot (26 letters and 10 digits), and we have 6 spots, we have a total of

36^6

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Event A happens if the password starts with either a, e, i, o or u. If we fix the first character, we're left with 36 characters available for each of the remaining 5 spots, leading to a total of

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So, the probability of event A, computed as the ratio between "good" cases and all possible cases, is

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Event B works exactly the same, since we're fixing the last spot, leaving 36 characters available for each of the first 5 spots. So, we have

P(A)=P(B)=\dfrac{5}{36}

As for the intersection, we want the first character to be a vowel, and the last character to be an even digits. There are 25 passwords satisfying this request:

axxxx0,\ axxxx2,\ axxxx4,\ axxxx6,\ axxxx8

exxxx0,\ exxxx2,\ exxxx4,\ exxxx6,\ exxxx8

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oaxxxx0,\ oxxxx2,\ oxxxx4,\ oxxxx6,\ oxxxx8

uxxxx0,\ uxxxx2,\ uxxxx4,\ uxxxx6,\ uxxxx8

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So, we have 25 cases with 4 vacant slots, leading to a probability of

P(A\cap B)=\dfrac{25\cdot 36^4}{36^6}=\dfrac{25}{1296}

Finally, you can compute the probability of the union using the formula

P(A\cup B)=P(A)+P(B)-P(A\cap B)

Since we already computed all these quantities.

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tigry1 [53]
F and E are congruent with the figure above
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