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horrorfan [7]
2 years ago
12

Given ∆ABC with vertices A(−4, −3), B(0, 0), C(2, −3) and ∆DEF with vertices D(3, 1), E(6, -3), F(3, −5), use the definition of

congruence in terms of rigid motion to show that ∆ABC ≅ ∆DEF. Describe each rigid motion in terms of coordinates (x, y
Mathematics
1 answer:
dimaraw [331]2 years ago
6 0

By SSS congruency criteria ΔABC ≅ ΔDEF

<h3>What is congruency?</h3>

Two figures or objects are congruent if they have the same shape and size, or if one has the same shape and size as the mirror image of the other.

The given vertices of the triangles are;

ΔABC: A(−4, −3), B(0, 0), C(2, −3)

ΔDEF:  D(3, 1), E(6, -3), F(3, −5)

The lengths of the sides of ΔABC are

AB = √((0+4)² + (0+3)²) = √25 = 5

BC = √((2-0)² + (-3 - 0)²) = √13  

AC = √((2+4)² + (-3 +3)²) = √36 = 6

The lengths of the sides of ΔDEF are;

DE = √25=5

EF = √13

DF = √36 = 6

As,

AB= DE, BC = EF , AC= DF

So, By SSS congruency criteria ΔABC ≅ ΔDEF

Learn more about this concept here:

brainly.com/question/6563819

#SPJ1

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4 0
3 years ago
Which of the following equations describes the line shown
wariber [46]
(-4,4) (2,1)
gradient = (1-4)/(2--4) = -1/2
y = mx + c
y = -1/2x + c
Replace point (2,1) in the equation
1=-1/2(2) +c
c = 2
Equation : y = -1/2x + 2
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Answer is C.
Hope it helped!
6 0
4 years ago
Find the equation of the line with slope = 2 and passing through (-3 , 4)
coldgirl [10]

Answer:

y = 2x + 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 2. thus

y = 2x + c ← is the partial equation

To find c substitute (- 3, 4) into the partial equation

4 = - 6 + c ⇒ c = 4 + 6 = 10

y = 2x + 10 ← equation of line

8 0
3 years ago
Read 2 more answers
NO LINKS!!!! Find the equation of the circle below​
inysia [295]

Answer:

(x+3)^2+(y-2)^2=9

Step-by-step explanation:

<u>Equation of a circle</u>

(x-a)^2+(y-b)^2=r^2

where:

  • (a, b) is the center
  • r is the radius

From inspection of the diagram, the center of the circle <em>appears</em> to be at point (-3, 2), although this is not very clear.  Therefore, a = -3  and  b = 2.

Substitute these values into the general form of the equation of a circle:

\implies (x-(-3))^2+(y-2)^2=r^2

\implies (x+3)^2+(y-2)^2=r^2

Again, from inspection of the diagram, the <u>maximum vertical point</u> of the circle appears to be at y = 5.  Therefore, to calculate the radius, subtract the y-value of the center point from the y-value of the maximum vertical point:

⇒ radius (r) = 5 - 2 = 3

Substitute the found value of r into the equation:

\implies (x+3)^2+(y-2)^2=3^2

Therefore, the final equation of the given circle is:

\implies (x+3)^2+(y-2)^2=9

7 0
2 years ago
Read 2 more answers
Solve for x.<br> (1/3) over 3 =x over 8
Ugo [173]

8/3=3x (cross multiplied to get this)

X=8/9 (divided both sides by 3)

Hope this helps :)

8 0
3 years ago
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