All categories

3 years ago

Find the slope of the line that passes through (-37, 47) and (26, 32).

1 answer:

4 0

(x1,y1) = (-37,47)
(x2,y2) = (26,32)

Now, m = (47-32) / (26+37)
m = 15 / 63
m = 5/21
So, the slope would be 5/21

Hope this helps!

You might be interested in

Suppose that you are asked to find a quadratic regression to model the height of a ball above the ground after it has been throw

Bogdan [553]

The y-intercept would represent the highest point. The graph will show a parabola and this point will only be reached once.

The x-intercept would be the starting point and the ending point. You can find total distance traveled with this.

7 0

3 years ago

Christy solved this problem. A store charged a customer $445.50 for 150 floor tiles . What is the price of each tile? Christy th

elixir [45]

The answer is A hope this helps

5 0

3 years ago

Read 2 more answers

What value of x is in the solution set of 3(х – 4) > 5х + 2? 0—10 ОООО

MakcuM [25]

X < -7 hope this helps

4 0

3 years ago

Find the surface area

xz_007 [3.2K]

Answer:

base -l*b - 13*6.5 - 84.5

6 0

3 years ago

A playground is being designed where children can interact with their friends in certain combinations. If there is 1 child, ther

mariarad [96]

<h2>Answer:</h2>

Recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

<h2>Step-by-step explanation:</h2>

In the question,

The number of interaction for 1 child = 0

Number of interactions for 2 children = 1

Number of interactions for 3 children = 5

Number of interaction for 4 children = 14

So,

We need to find out the pattern for the recursive equation for the given conditions.

So,

We see that,

$a_{1}=0\\a_{2}=1\\a_{3}=5\\a_{4}=14\\$

Therefore, on checking, we observe that,

$a_{n}=a_{n-1}+(n-1)^{2}$

On checking the equation at the given values of 'n' of, 1, 2, 3 and 4.

At,

n = 1

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{1}=a_{1-1}+(1-1)^{2}\\a_{1}=0+0=0\\a_{1}=0$

which is true.

At,

n = 2

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{2}=a_{2-1}+(2-1)^{2}\\a_{2}=a_{1}+1\\a_{2}=1$

Which is also true.

At,

n = 3

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{3}=a_{3-1}+(3-1)^{2}\\a_{3}=a_{2}+4\\a_{3}=5$

Which is true.

At,

n = 4

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{4}=a_{4-1}+(4-1)^{2}\\a_{4}=a_{3}+9\\a_{4}=14$

This is also true at the given value of 'n'.

Therefore, the recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

3 0

3 years ago