Answer:
43.43/43
Step-by-step explanation:
<span>B. parallelogram, rhombus</span>
The sum of n terms of a geometric sequence with first term "a" and common ratio "r" is given by
You have a=21, r=3, so the sum of 10 terms is
The appropriate choice is the 2nd one:
620,004
#1: 214 tickets split 9 ways does not work out to an integer number. Nobody wants 2/3 of a ticket, right?
So the trick here is to determine the first multiple of 9 greater than 214.
Note that 214/9 = 23.8. No good. Not an integer.
Multiply 23 by 9; we get 207. Multiply 24 by 9; we get 216.
So, given that we have 214 tickets already, we need 2 more, to make 216.
Check: Is 216 divisible by 9 without a remainder? Yes. Then each of the 9 students will get 24 tickets.
The rest of the problems are somewhat similar to this one.
See whether you can do the next one, #2.
If you'd share your results, I'd be happy to comment on what you've done.
Answer: cos(x) = 0
Good luck !
