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Olegator [25]
3 years ago
12

What is the approximate value of 42 using benchmark

Mathematics
1 answer:
cestrela7 [59]3 years ago
5 0
√42
6²=36
7²=49
(6 1/2)² = 42.25
√42 ≈ 6.5
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Identify the x-intercepts
Molodets [167]

Answer:

4)  ( 5, 0) and ( -5, 0)

4 0
3 years ago
When 3 is subtracted from one third of a number n, the result is less than 6. Which inequality and solution represent this situa
MArishka [77]

Answer:

1/3n-3÷6

Step-by-step explanation:

3 is subtraced form 1/3

3 0
2 years ago
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Which method would be best (quickest) for solving the system below:<br> 3x - 4y = -2<br> y = 2x + 1
taurus [48]
To solve with Elimination:

Write the equations under one another, like this:

2x - y = -1
+ 3x + 4y = 26

Ideally, we would like for one of the variables to be eliminated when we add vertically (straight down). But if we add them as they are this does not happen. We must manipulate one of the equations so that it will happen. Again, you can try to eliminate either x or y. I always look for a term that has a coefficient of 1 (or negative 1). So, let's use that y from the first equation again.

If the coefficient of the y in the other equation is POSITIVE 4, then I need the coefficient from the first equation to be its opposite, NEGATIVE 4. To do this, simply multiply the first equation by 4, this will create MAGIC!

4( 2x - y = -1)
+ 3x + 4y = 26

Be certain to Distribute across the entire first equation, so multiply all three terms by 4.

8x - 4y = -4
+ 3x + 4y = 26

Now add straight down (vertically). The y term will be eliminated.

11x = 22

Divide both sides of the equation by 11.

x = 2

Almost there! Now, substitute the 2 in for x in either of the original equations. Either one will work. I'm gonna use the second equation.

3x + 4y = 26

3(2) + 4y = 26

6 + 4y = 26

Subtract 6 from both sides of the equation.

4y = 20

Divide both sides of the equation by 4.

y = 5

That's it! There it is again. Put it all together. If x = 2 and y = 5, then the solution is the ordered pair, (2,5).
8 0
2 years ago
A certain television is advertised as a 50-inch TV (the diagonal length). If the width of
Anvisha [2.4K]

Hello there i hope you are having a great day :) Your question: A certain television is advertised as a 50-inch TV (the diagonal length). If the width of  the TV is 14 inches, how many inches tall is the TV?

So you would need to used the Pythagorean theorem that would be

c^2 = a^2 + b^2

So this would equal letter C as The hypotenuse of the right angle and also letter A and B are the stands on the triangle so C would equal 50 inches and A and B would equal 14 inches.

Then the Hard bit so you would be,

1) a^2 = c^2 - b^2

2) a = √c^2 - b^2

3) a =  50^2 - 14^2

4) a = √ 2,500 - 196

5) a = √2,304

6) A = 26

So the answer would be 26 Hopefully ❤

3 0
3 years ago
Guys please this is my second time posting this I really need help. And if you answer this you can answer my other same question
spayn [35]

Answer: F and H I think are vertical

Step-by-step explanation:

I'm sorry i couldn't help you

4 0
3 years ago
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