the probability that in bot rolls we have a sum of, at most, 8, is:
P = 47/ 1,296 = 0.036
<h3>
How to find the probability?</h3>
The pair is tossed twice. A pair of dice has 36 possible outcomes, so if we toss twice the pair, the total number of outcomes is:
36*36 = 1,296
Now if we define the outcomes as:
{dice 1 (roll1), dice2(roll1), dice 1 (roll2), dice2(roll2) }
The outcomes that give at most a sum of 8 are:
{1, 1, 1, 1}
{2, 1, 1, 1} ( 3 permutations)
{2, 2, 1, 1} ( 6 permutations).
{2, 2, 2, 1} ( 3 permutations)
{3, 1, 1, 1} ( 3 permutations)
{3, 2, 1, 1} ( 12 permutations)
{3, 3, 1, 1} (6 permutations)
{4, 1, 1, 1} (3 permutations)
{4, 2, 1, 1} (6 permutations)
{5, 1, 1 , 1} (3 permutations)
{2, 2, 2, 2}
These are all the outcomes that give a sum of, at most, 8.
If we add all the outcomes we get 47 outcomes.
Then the probability that in bot rolls we have a sum of, at most, 8, is:
P = 47/ 1,296 = 0.036
If you want to learn more about probability:
brainly.com/question/25870256
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