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3 years ago

I had to watch these videos with the problem but i didn’t actually watch it so help pls

Mathematics

1 answer:

vodomira [7]3 years ago

8 0

Answer:

u have to watch the videos so it can help u with the problem

Step-by-step explanation:

It will be easier if u watch them

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4sin^2 + 13cos^2 = 7. Find cos <br><br> Please read the picture question carefully and help !!

Vanyuwa [196]

4 sin^2 θ + 13cos^2 θ = 7
sin^2 θ = 1 - cos^ θ
4 - 4cos^2 θ + 13cos^2 θ = 7
9cos^2 θ = 3
cos^2 θ = 1/3
cos θ = # (1/3) # - square root
Square root of (1/3) has +1/3 and -1/3 as values of cos
Find the key angle by doing the cos inverse of #1/3
K.A = cos^-1 #(1/3) = 0.955
θ lies in all 4 quadrants
The values of θ are:
θ = 0.955, 2.186, 4.096, 7.23
Ignore 0.955, 2.186, 4.096, 7.23 as they are out of range pi/2 = 1.571
The the value of θ = 0.955 = 0.96 (to 2 d.p) radian

Hope it helped!

5 0

3 years ago

Solve by factoring<br> x^2-8x-9 = 0

3241004551 [841]

Answer:

the answer is ( x-9) (x+1) = 0

Step-by-step explanation:

more to the solution is x= -1, 9

4 0

3 years ago

Read 2 more answers

What's the slope and y-intercept of the equation 3x + 4y = 8?

Anna71 [15]

Answer:

Slope = -3/4

y-intercept = 2

Step-by-step explanation:

$3x+4y = 8\\\therefore 4y = -3x +8\\\therefore y = \frac{-3}{4}x+ \frac{8}{4}\\\therefore y = \frac{-3}{4}x+2\\Equating \: it \: with\: \\y=mx+b\\Slope\:(m) = \frac{-3}{4}\\y-intercept\:(b) = 2$

6 0

3 years ago

Read 2 more answers

3 part question-Show work for part a and part c

blagie [28]

Answer:

Step-by-step explanation:

Part A: You can only use Pythagorean's Theorem on a right triangle.

Part B: The side across from the right angle is the hypotenuse. It has a length of 15.

Part C: To find the missing side using Pythagorean's Theorem:

$a^2+11^2=15^2$ and

$a^2+121=225$ and

$a^2=104$ and

a = 10.20

5 0

3 years ago

Brainliest and Five Stars for correct answers

wel

$\bf \lim\limits_{x\to 9}~\cfrac{x^2-81}{x-9}\implies \cfrac{\stackrel{\textit{difference of squares}}{x^2-9^2}}{x-9}\implies \cfrac{\underline{(x-9)}(x+9)}{\underline{(x-9)}}
\\\\\\
\lim\limits_{x\to 9}~x+9\implies (9)+9\implies 18$

3 0

3 years ago