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Aloiza [94]
2 years ago
8

PLEASE HELP ASAP!!!!!!!1

Mathematics
1 answer:
melisa1 [442]2 years ago
8 0

The series diverges. You Consider concluding this because the series is in arithmetic progression.

<h3>What is an arithmetic sequence?</h3>

An arithmetic sequence is a sequence of integers with its adjacent terms differing with one common difference.

The explicit formula for any arithmetic series is given by the formula,

a_n = a_1 + (n-1)d

where d is the difference and a₁ is the first term of the sequence.

The given series of numbers 1/4+3/2+11/4+4+21/4+.... is an arithmetic series because the difference between any two consecutive terms is 5/4. Therefore, the blanks can be filled as,

The series diverges. You Consider conclude this because the series is in arithmetic progression.

Learn more about the Arithmetic sequence:

brainly.com/question/3702506

#SPJ1

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IgorC [24]
17+13=30-8=22
I did 17 plus 13 which equals 30, then I took 30 and subtracted 8 which equals 22!!!
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If you have two nickels and two dimes and nine pennies how much will that be
Drupady [299]
39cents would be the answer
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Evaluate |bc|, given a = 5, b = -3, and c = -2.
Anni [7]

Answer:

6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • |Absolute Value| - makes any number positive

Step-by-step explanation:

<u>Step 1: Define</u>

|bc|

a = 5

b = -3

c = -2

<u>Step 2: Evaluate</u>

  1. Substitute:                    |-3 · -2|
  2. Multiply:                        |6|
  3. Evaluate:                       6
7 0
2 years ago
HELP ME PLEASE
aivan3 [116]

Answer:

Answer is A

Step-by-step explanation:

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2 years ago
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How many ways can eight letters be arranged into groups of five where order matters and the first two letters are already chosen
fenix001 [56]

Answer:

120

Step-by-step explanation:

Since we're dealing with a problem where the order matters and the first two letters are already chosen we need to subtract the number of letters and the number of available slots per group.

We use the permutation formula to find the answer, but before that let's check values.

n = 8

k = 5

Now since there are two letters already chosen we have to deduct two from both the value of n and k.

n = 6

k = 3

Now we can use the permutation formula:

_{n}P_{k}=\dfrac{n!}{(n-k)!}

_{6}P_{3}=\dfrac{6!}{6-3)!}

_{6}P_{3}=\dfrac{6!}{3!}

_{6}P_{3}=\dfrac{6*5*4*3*2*1}{3*2*1}

The 3*2*1 cancels out and leaves us with:

_{6}P_{3}=6*5*4

_{6}P_{3}=120

So there are 120 possible ways to arrange eight letters into groups of five where order matters and the first two letters are already chosen.

6 0
3 years ago
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