A rectangle, presumably, as the cross section is going to be whatever shape the outward faces are (in the case of a vertical cross section like this one)
Answer:
<h2>30% is enrolled out-of-district.</h2>
Step-by-step explanation:
According to the word problem, the number is increased by 50%.
To increase a number by a percent, multiply the number and the percent.
We can do this by changing both percents to decimals.
To change a percent to a decimal, divide it by 100.
The number is INCREASED by 50% so 0.5 would become 1.5.
<h2>0.3 = 30%.</h2>
Answer:
The width which gives the greatest area is 7.5 yd
Step-by-step explanation:
This is an application of differential calculus. Given the area as a function of the width, we simply need to differentiate the function with respect to x and equate to zero which yields; 15-2x=0 since the slope of the graph is zero at the turning points. Solving for x yields, x=7.5 which indeed maximizes the area of the pen
X^2-7x+38=5x+3
x^2-7x+38-5x-3=5x+3-5x-3
x^2-12x+35=0
Factoring:
(x-5)(x-7)=0
Two solutions:
x-5=0→x-5+5=0+5→x=5
x-7=0→x-7+7=0+7→x=7
Answer: x=5 and x=7
Answer: Options B. 7 and D. 5
Answer:
$80 - $20 = $60 left.
Step-by-step explanation:
