Answer:
C. Personal Reference introduction
Explanation:
This introduction type talks about a subject (State University) by relating the speaker or his experience to the subject.
(A) Quotation is something that is being said by someone. So whether or not this speaker related himself to the university, what he said would still have been taken as a quote or would be put in quotation marks when written down.
(B) A Rhetorical Question is one which is asked without the intent of getting an answer. First of all, there is no question in this speaker's speech.
(D) "Story" would have been the answer if there was no option (C) but the fact that option C exists and more perfectly describes his speech, makes (D) refutable.
For the answer to the question above, they are based on the renewable and exhaustible resources of the earth that is according to the worth of natural resources in contemporary economics. Examples of exhaustible or nonrenewable resources are oil and coal. You can't replace them when they are depleted completely. On the other hand, the renewable are resources is like labor
Missing question: Which project should be implemented based on net present value?
Solution:
NPV = -Co + C1/(1+r) + C2/(1+r)^2 + ... + Cn/(1+r)^n
Project A
NPV = -95000 + 65000/(1+0.1) + 75000/(1+0.1)^2 = $26,074.38
Project B
NPV = -120000+ 64000/(1+0.1) + 67000/(1+0.1)^2 + 56000/(1+0.1)^3 + 45000/(1+0.1)^4 = $66,362.95
The rule: The project with higher NPV is chosen for implementation. Based on the NPVs calculated, project B is the most viable.
Answer:
a. 0.0124
b. 12
c. 0.0054
d. 5
e. advantage of reducing process variation is that probability of defect item is decreased
Explanation:
mean = 6
SD = 0.1
a)probability of a defect = 1 - P(5.75 <X <6.25)
= 1 - P(-2.5<Z <2.5)= = 1 - 2(0.9938-0.5) = 2(1-0.9938) = 2*0.0062 = 0.0124
b)In a production run of 1000 parts,number of defects would be found = 1000*0.124 = 12.4 = 12
c)1 - P(5.75 <X <6.25) = 1- P(-0.25/0.09 <Z < 0.25/0.09) = 1- P(-2.777 <Z<2.777)= 1 - 2 (0.9973 -0.5)
= 2 ( 1 - 0.9973) = 2*(0.0027) =0.0054
d)In a production run of 1000 parts,number of defects would be found = 1000*0.0054 = 5.4 = 5
e) advantage of reducing process variation is that probability of defect item is decreased.
Solution:
S.NO. Accounts title and Explanations Debit Credit
1 Cash $25,000
Accumulated Depreciation- Machine A $63,960
Gain on Dispose: $10,400
Machine A $78,560
Accumulated Depreciation - Machine B $16,500
Loss on Disposal $10,700
Machine B $27,200
Note: -When the net value of the commodity disposed of is smaller than the amount paid, there is a benefit. If the worth of the book is MOT, there is a cost.
