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oksano4ka [1.4K]
3 years ago
6

Plz Help! ASAP!!!!

Mathematics
1 answer:
vekshin13 years ago
7 0

Answer:

Do you still need help?

Step-by-step explanation:

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How are you in the bet nobody’s not going to help me on this question
Nataliya [291]

Answer:

See below.

Step-by-step explanation:

Party A

y = x^2 + 1

For each value of x in the table, substitute x in the equation with that value and evaluate y.

x = -2: y = (-2)^2 + 1 = 4 + 1 = 5

x = -1: y = (-1)^2 + 1 = 1 + 1 = 2

Do the same for x = 0, x = 1, x = 2

x     y

-2   5

-1    2

0    1

1     2

2    5

Part B

Look at points (-2, 5) and (-1, 2). The change in x from (-2, 5) to (-1, 2) is 1. The change in y is -3.

Now let's look at two other points which have a change in x of 1. Look at points (0, 1) and (1, 2). The change in x from (0, 1) to (1, 2) is 1. The change in y is 1.

You can see that for the first two points, a change of 1 in x produces a change of -3 in y, but for the second two points, the same change of 1 in x produce a change of 1 in y. Since the same change of x does not always produce the same change in y, the function is nonlinear.

Answer: A

4 0
3 years ago
Nate is 10/9/12 years old. How old will he be in 2/1/12 more years
EastWind [94]

The answer is B. 10 9/12 + 2 1/12= 12 10/12. 12÷2=6 10÷2=5 making the answer 12 5/6
5 0
3 years ago
. Use the number line to illustrate the difference: -3-(-7)​
Oxana [17]

omhhhhhhfffffffyyyyuuuuu

8 0
3 years ago
Read 2 more answers
Least to greatest -.6 -5/8 -7/12 -.72
svlad2 [7]

It would be:

-.72 < -5/8 < -.6 < -7/12


4 0
3 years ago
Graph the exponential function<img src="https://tex.z-dn.net/?f=%20f%28x%29%3D%5Cfrac%7B1%7D%7B2%7D%5E%7Bx%7D%20%20" id="TexForm
tatyana61 [14]

f(x)=\left(\dfrac{1}{2}\right)^x\\\\for\ x=-3\to y=\left(\dfrac{1}{2}\right)^{-3}=2^3=8\to(-3,\ 8)\\\\for\ x=-2\to y=\left(\dfrac{1}{2}\right)^{-2}=2^2=4\to(-2,\ 4)\\\\for\ x=-1\to y=\left(\dfrac{1}{2}\right)^{-1}=2^1=2\to(-1,\ 2)\\\\for\ x=0\to y=\left(\dfrac{1}{2}\right)^0=1\to(0,\ 1)\\\\for\ x=1\to y=\left(\dfrac{1}{2}\right)^1=\dfrac{1}{2}\to\left(1,\ \dfrac{1}{2}\right)\\\\for\ x=2\to y=\left(\dfrac{1}{2}\right)^2=\dfrac{1}{4}

3 0
3 years ago
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