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2 years ago

The table shows results of an experiment that was replicated.

Mathematics

1 answer:

KiRa [710]2 years ago

4 0

The option that best describes the experiment is accurate and reproducible.

<h3>What option describes the data?</h3>

All the values from the experiment are close in value to the accepted value. This indicates that the experiment is accurate. Two experiments yield the same values. This indicates that the experiment is reproducible.

Here is the table used in answering the question:

Accepted Value: 130

Experiment 1 129

Experiment 2 131

Experiment 3 129

Experiment 4 132

To learn more about experiments, please check: brainly.com/question/14019529

#SPJ1

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A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 2

Shalnov [3]

Answer:

The expected winnings for a person buying 1 ticket is -0.2.

Step-by-step explanation:

Given : A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 25 cents each, find the expected winnings for a person buying 1 ticket.

To find : What are the expected winnings?

Solution :

There are one first prize, 2 second prize and 20 third prizes.

Probability of getting first prize is $\frac{1}{20000}$

Probability of getting second prize is $\frac{2}{20000}$

Probability of getting third prize is $\frac{20}{20000}$

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each.

So, The value of prizes is

$\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10$

If 20000 tickets are sold at 25 cents each i.e. $0.25.

Remaining tickets = 20000-1-2-20=19977

Probability of getting remaining tickets is $\frac{19977}{20000}$

The expected value is

$E=\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10-\frac{19977}{20000}\times 0.25$

$E=\frac{1000+600+200-4994.25}{20000}$

$E=\frac{-3194.25}{20000}$

$E=-0.159$

Therefore, The expected winnings for a person buying 1 ticket is -0.2.

3 0

3 years ago

Math problem+Zoey, a Gelada Baboon, is tied to one of the outside corners of a regular hexagon-shaped research facility, where h

dexar [7]

Answer

The monkey will be able to cover an area of 22.86 meters which is equivalent to two sides and half of the building.

Step-by-step explanation:

The length of the monkeys rope = 75 feet long

Each side of the hexagon shaped facility = 30 feet

Note that, 1 feet = 0.3048 m

if we convert 30 feet to Meter, we have,

30 × 0.3048 = 9.144

Therefore, 30 + 30 +15 = 75 which is equivalent to the two side and half side of the hexagon shaped building

75 feet × 0.304 meter = 22.86 meters.

So the total area the monkey will be able to cover will be

= 22.86 Meters which is equivalent to two sides and half of the hexagon shape building.

8 0

3 years ago

Pls help with math ASAP

9966 [12]

I think 6,1 and the upper point is -6,11

7 0

3 years ago

6x10 to the power of zero

Bezzdna [24]

Hello There!

6 x 10 $^{0}$ = 6.

Hope This Helps You!
Good Luck :)

3 0

3 years ago

Read 2 more answers

An observer in a hot air balloon sights a building that is 50 m from the balloon's launch point. The balloon has risen 165 m. Wh

Kaylis [27]

Notice the picture,
recall your SOH, CAH, TOA
$\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}$

you have,
opposite side, 165
adjacent side, 50
and the angle

that means, we'll need Mrs. tangent
thus
$\bf tan(\theta)=\cfrac{opposite}{adjacent}\implies tan(\theta)=\cfrac{165}{50}
\\ \quad \\
 tan^{-1}\left[ tan(\theta) \right]=tan^{-1}\left[ \cfrac{165}{50} \right]
\\ \quad \\
\theta=tan^{-1}\left[ \cfrac{165}{50}\right]
\\ \uparrow \\
 \textit{angle of elevation}\iff\textit{angle of depression}$

4 0

3 years ago