What is the total number of digits used when the first 2002 positive even integers are written?
1 answer:
The total number of digits used when the first 2002 positive even integers are written is 4 digits
<h3>How to find the number of sequence?</h3>
Using arithmetic sequence,
nth term = a + (n - 1)d
where
- a = first term
- d = common difference
- n = number of terms
a = 2
d = 2
nth term = 2 + (2002 - 1)2
nth term = 2 + 4002
nth term = 4004
learn more on sequence here: brainly.com/question/15456604
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Answer:
4
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
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m=8/2
m=4
Fraction: 1/1000
Decimal: .001
The answer is ..02040816326