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Mama L [17]
2 years ago
12

What is the total number of digits used when the first 2002 positive even integers are written?

Mathematics
1 answer:
Luda [366]2 years ago
7 0

The total number of digits used when the  first 2002 positive even integers are written is 4 digits

<h3>How to find the number of sequence?</h3>

Using arithmetic sequence,

nth term = a + (n - 1)d

where

  • a = first term
  • d = common difference
  • n = number of terms

a = 2

d = 2

nth term = 2 + (2002 - 1)2

nth term = 2 + 4002

nth term = 4004

learn more on sequence here: brainly.com/question/15456604

#SPJ1

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Step-by-step explanation:

Perfect square trinomials come in the form a² + 2ab + b², which is equal to (a + b)². In the presented trinomial, we can immediately identify that <u>a = x, and b² = c</u>, but we need to find the numerical value of c.

To do this, note that the middle term, or <u>2ab, corresponds with (is equal to) 30x</u>. We know that a = x, and thus, <u>2ab = 2bx</u>. Now, 2bx and 30x are corresponding terms; thus, <u>2bx = 30x</u>.

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