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3 years ago

If you could answer both, that would be amazing:)

Mathematics

1 answer:

sveticcg [70]3 years ago

7 0

The first question is “32.4”
I’ll come back if I find the other

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Sea level is considered to be 0 feet. A probe released at sea level dropped at a constant rate for 3.25 minutes, reaching an ele

mash [69]

Thank you for posting your question here at brainly. The probe's elevation relative to sea level after the first minute, the probe dropped 11 feet per minute, therefore, it dropped 11 feet in the first minute. I hope the answer helps you.

8 0

3 years ago

Tamar has 24 pencils. 4/6 of the pencils need to be sharpened. How many pencils need to be sharpened?

zavuch27 [327]

Answer:

16 pencils need to be sharpened

Step-by-step explanation:

6 divided by 24 = 4 x 6 = 24 switch the 6 with a 4 and its 4 x 4= 16

6 0

3 years ago

Read 2 more answers

Guys, please help me with problem.

likoan [24]

Answer:

$\boxed{\bold{-25}}$

Step-by-step explanation:

Remove parenthesis: (a) = a

$\bold{\frac{-5^2+10^2}{-2\cdot \:5\cdot \:3+3^3}}$

$\bold{-5^2+10^2: \ 75}$

$\bold{\frac{75}{-2\cdot \:5\cdot \:3+3^3}}$

$\bold{-2\cdot \:5\cdot \:3+3^3: \ -3}$

$\bold{\frac{75}{-3}}$

Apply fraction rule: $\bold{\frac{a}{-b}=-\frac{a}{b}}$

$\bold{-\frac{75}{3}}$

Divide $\bold{\:\frac{75}{3}: \ 25}$

$\bold{-25}$

Regards,

Mordancy

8 0

3 years ago

Any help would be greatly appreciated

Andreas93 [3]

Answer:

$\boxed{\df \ \ \ \dfrac{b^7}{3} \ \ \ }$

Step-by-step explanation:

$\dfrac{9h^2b^8}{27h^2b}=\dfrac{h^{2-2}b^{8-1}}{3}=\dfrac{b^7}{3}$

as 27=9*3

3 0

3 years ago

There are 10 colored balls in a box ( 5 red, 3 blue, 2 green ). What is the probability of picking out a red ball and then a blu

Ksenya-84 [330]

At the beginning you have 10 balls, 5 of which are red. So, the chance of picking a red ball with the first pick is

$\dfrac{5}{10}=\dfrac{1}{2}$

When it comes to the second pick, you have 9 balls (because you didn't replace the first red ball), 3 of which are blue. So, you pick a blue ball with the second pick with probability

$\dfrac{3}{9}=\dfrac{1}{3}$

The two events will occur one after the other with the product of the probabilities:

$\dfrac{1}{2}\cdot\dfrac{1}{3}=\dfrac{1}{6}$

7 0

3 years ago