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FrozenT [24]
2 years ago
15

If there are 300 cars and 80 of them are black, what percent of the cars are black

Mathematics
1 answer:
kari74 [83]2 years ago
5 0

The percentage of cars that are black when 80 cars of 300 cars are black is 26.67 or 26 2/3 %.

The percentage is similar to the fractional representation of quantities, where the quantity is shown as a part of the whole, but here the whole is fixed to be 100.

To derive a percentage in fractional form, we divide it by 100.

To derive a fractional form in percentage, we multiply it by 100.

In the question, we are given that 80 cars of 300 cars are black.

We are asked the percentage of cars that are black.

The fraction representing black cars of whole cars can be shown as 80/300 = 4/15.

To convert this into a percentage, we multiply it by 100.

Thus, the percentage of cars that are black = 4/15 * 100% = 80/3% = 26 2/3% = 26.67%.

Thus, the percentage of cars that are black when 80 cars of 300 cars are black is 26.67 or 26 2/3 %.

Learn more about percentages at

brainly.com/question/843074

#SPJ4

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Step-by-step explanation:

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Let k be an integer. Suppose there is a triangle with legs of length 16 and 2k+1. Then by the Pythagorean theorem, the length of the hypotenuse should be

\sqrt{16^2+(2k+1)^2}=\sqrt{4k^2+4k+257}

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I am redesigning a rectangular prism in geometry where I have to minimize the surface area while maintaining the same volume. I
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Strategy:

You will need to make use of the formulas for volume and area of the shapes you have chosen.

... volume of a sphere = (4/3)πr³

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You will have to use the volume equation to find the radius of the sphere with the desired volume. Then use the area formula to verify the area is smaller than for your rectangular prism. (A sphere has the smallest surface area for a given volume of any figure.)

___

For your pyramid, it's a bit more complicated. You can use the formula for volume to find a relationship between the side length and the height. Then you can solve for height and put that expression into the equation for surface area. Now, you have an equation for surface area as a function of side length, which you can use to choose side lengths that give surface area in the range you want. You may find a graphing utility to be helpful for this.

... volume of a pyramid = (1/3)b^2h . . . . . b is the edge length of the base; h is the verical height.

... area of a pyramid = b^2 + 2bs, where s is the slant height: s=√((b/2)^ +h^2)

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The cylinder is solved essentially the same way the pyramid is solved, except the formulas are slightly different.

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If I did it right, a pyramid with a base edge length of 4 or 5 inches (or somewhere between) should give a smaller surface area for the volume you want.

For the cylinder, the radius may be around 2 or 2.1 inches.

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