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AVprozaik [17]
3 years ago
5

Pls help Being timed

Mathematics
2 answers:
Volgvan3 years ago
8 0

-6-8+12 the answer to this is -2 so b

umka2103 [35]3 years ago
3 0
(-6)-(+8)-(-12)
-6-8+12
-14+12
-2
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Quadrilateral ABCD has vertices A(1,0) B(5,0) C (7,2) D(3,2). Use slope to prove that ABCD is a parallelogram.
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Answer:

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Step-by-step explanation:

The vertices of quadrilateral ABCD are A(1,0) B(5,0) C (7,2) D(3,2).

The slope of side AB is

M_{AB}=\frac{0-0}{5-1} =\frac{0}{4}=0

The slope of side BC is

M_{BC}=\frac{2-0}{7-5} =\frac{2}{2}=1

The slope of side CD is

M_{CD}=\frac{2-2}{3-7} =\frac{0}{-4}=0

The slope of AD is

M_{AD}=\frac{2-0}{3-1} =\frac{2}{2}=1

AD \parallel BC

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We see that the opposite sides of the quadrilateral ABCD are equal.

Hence the quadrilateral is a parallelogram

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