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1 year ago

Which ordered pairs make both inequalities true? Check all that apply.

Mathematics

1 answer:

Andrej [43]1 year ago

7 0

We can actually deduce here that the ordered pairs that make both inequalities true are:

(1,1)
(2, 2)

<h3>What is inequality?</h3>

An inequality is known to be an expression that shows that certain variables or values are not equal to each other. It is usually seen in an inequality expression as:

> (greater than)
< (less than)
≥ (greater than or equal to)
≤ (less than or equal to).

We see the attached image that shows the graph of inequality and which completes the question.

The options that complete the question are:

A. –2, 2

B. (0, 0)

C. (1,1)

D. (1, 3)

E. (2, 2)

When we insert the values of each axes into the inequality expressions given, we will discover that the ordered pairs that the inequalities true is (1,1) and (2, 2).

Learn more about inequality on brainly.com/question/25275758

#SPJ1

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Convert 1/15 into a decimal correct to 2 decimal places

Citrus2011 [14]

Answer:

$\frac{1}{15} = 0.\overline{66}$

Step-by-step explanation:

We proceed to show the procedure to calculate the given fraction into a decimal form:

1) Since numerator is less than denominator, the integer component of the decimal number is zero:

$\frac{1}{15} = 0.xx$

2) We multiply the numerator by 10 and find the tenth digit:

$\frac{10}{15} = 0$

Then,

$\frac{1}{15} = 0.0xx$

3) We multiply the fraction in 2) by 10 and find the hundredth digit:

$\frac{100}{15} = 6$

Then,

$\frac{1}{15} = 0.66x$

And the remainder is:

$r = 100-15\times 6$

$r = 10$

4) We multiply the remainder by 10 and divide this result by the denominator to determine the thousandth digit:

$\frac{100}{15} = 6$

Then,

$\frac{1}{15} = 0.666$

This question asks us to write a decimal correct to 2 decimal places, which has the characteristic that is infinite periodical decimal. Then, the result correct to 2 decimal places is:

$\frac{1}{15} = 0.\overline{66}$

3 0

2 years ago

Help with this proof

mixer [17]

Essentially, what we need to do here is prove that BE=EC, BE=CB, and.or CE=BC therefore making it isosceles. With ∠AEC=∠DEB, we know AE=DE, so EC=EB (the points go in order). Therefore, as EC=EB, BEC is isosceles (it has at least 2 equal sides).

Feel free to ask further questions!

7 0

3 years ago

What type of power function is represented in the table?

Alisiya [41]

It is quadratic your welcome

7 0

3 years ago

Please help with this question

11111nata11111 [884]

Answer:

QR and CD

Step-by-step explanation:

TQRS is similar to BCDE. Align the letters.

T Q R S

B C D E

Some examples of corresponding sides.

TS and BE

TQ and BC

6 0

3 years ago

The length of a rectangle is x times the square root of 100. The width is one-half y more than three-halves x. Given that the ar

pashok25 [27]

Area=length x width
A=10x(3/2 x + 1/2 y).
Now Distribute...
A=30x^2/2 + 10xy/2)
Now simplify fractions...
A=15x^2 + 5xy= 125

So I believe your answer is D)

7 0

3 years ago

Read 2 more answers