Which ordered pairs make both inequalities true? Check all that apply.
1 answer:
We can actually deduce here that the ordered pairs that make both inequalities true are:
- (1,1)
- (2, 2)
An inequality is known to be an expression that shows that certain variables or values are not equal to each other. It is usually seen in an inequality expression as:
- > (greater than)
- < (less than)
- ≥ (greater than or equal to)
- ≤ (less than or equal to).
We see the attached image that shows the graph of inequality and which completes the question.
The options that complete the question are:
A. –2, 2
B. (0, 0)
C. (1,1)
D. (1, 3)
E. (2, 2)
When we insert the values of each axes into the inequality expressions given, we will discover that the ordered pairs that the inequalities true is (1,1) and (2, 2).
Learn more about inequality on brainly.com/question/25275758
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Answer:
-
Step-by-step explanation:
A root with square root or under root is only obtained when we take the square root of both sides. Remember that when we take a square root, there are two possible answers:
- One answer with positive square root
- One answer with negative square root
For example, for the equation:
If we take the square root of both sides, the answers will be:
Only getting one solution with square root is not possible. Solutions with square root always occur in pairs.
For given case, the roots are 6 and . Therefore, the 3rd root of the polynomial function f(x) had to be -
It seems you made error while writing option B, it should be - square root of 5.
Answer:
Step-by-step explanation:
Hope this helped!
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