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1 year ago

Which ordered pairs make both inequalities true? Check all that apply.

Mathematics

1 answer:

Andrej [43]1 year ago

7 0

We can actually deduce here that the ordered pairs that make both inequalities true are:

(1,1)
(2, 2)

<h3>What is inequality?</h3>

An inequality is known to be an expression that shows that certain variables or values are not equal to each other. It is usually seen in an inequality expression as:

> (greater than)
< (less than)
≥ (greater than or equal to)
≤ (less than or equal to).

We see the attached image that shows the graph of inequality and which completes the question.

The options that complete the question are:

A. –2, 2

B. (0, 0)

C. (1,1)

D. (1, 3)

E. (2, 2)

When we insert the values of each axes into the inequality expressions given, we will discover that the ordered pairs that the inequalities true is (1,1) and (2, 2).

Learn more about inequality on brainly.com/question/25275758

#SPJ1

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2 years ago

For the graphed exponential equation, calculate the average rate of change from x = −3 to x = 0.

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Answer:

$-\frac{7}{3}$

Step-by-step explanation:

To solve this, we are using the average rate of change formula:

$m=\frac{f(b)-f(a)}{b-a}$

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$a$ is the first point

$b$ is the second point

$f(a)$ is the function evaluated at the first point

$f(b)$ is the function evaluated at the second point

We want to know the average rate of change of the function $f(x)=0.5^x-6$ form x = -3 to x = 0, so our first point is -3 and our second point is 0. In other words, $a=-3$ and $b=0$ .

Replacing values

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3 years ago

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Answer:

There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.

It would be unusual to randomly select a person aged 40 years or older who is male and jogs.

Step-by-step explanation:

We have these following probabilities.

A 13.9% probability that a randomly selected person aged 40 years or older is a jogger, so $P(A) = 0.13$ .

In addition, there is a 15.6% probability that a randomly selected person aged 40 years or older is male comma given that he or she jogs. I am going to say that P(B) is the probability that is a male. $P(B/A)$ is the probability that the person is a male, given that he/she jogs. So $P(B/A) = 0.156$

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So it would be unusual to randomly select a person aged 40 years or older who is male and jogs.

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