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Len [333]
2 years ago
14

Please solve this thank you!

Mathematics
2 answers:
SSSSS [86.1K]2 years ago
6 0

Answer:

1024x^{40}

Step-by-step explanation:

So the first step is to add like terms since you can simplify the numerator by adding the two values sine they have the same variable and degree.

Add like terms:

[\frac{8x^9}{2x}]^5

Divide by 2x (divide coefficient by 2, subtract coefficient degrees)

[4x^8]^5

Multiply exponents and raise 4 to the power of 5

1024x^{40}

The reason you multiply exponents is because you can think about it like this:

(4 * x * x * x * x * x * x * x * x) (this has one 4 and 8 x's because x is raised to the power of 8. Now if you do that 5 times which is what the exponent is doing you're going to have 40 x's and 8 4's. So it's essentially

(4 * x * x * x * x * x * x * x * x) * (4 * x * x * x * x * x * x * x * x) * (4 * x * x * x * x * x * x * x * x) * (4 * x * x * x * x * x * x * x * x) * (4 * x * x * x * x * x * x * x * x). If you group like terms you'll get (4 * 4 * 4 * 4 * 4) *  (x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x). Which simplifies to 4^5 * x ^ (8 * 5) which further simplifies to the answer 1024x^40

Tamiku [17]2 years ago
4 0

Answer:

1024x^40

Step-by-step explanation:

Apply exponent rule: (a/b)^c = a^c / b^c = (5x^9 + 3x^9)^5 / (2x)^5


Simplify:

(5x^9 + 3x^9)^5: 32768x^45

= 32768x^45 / (2x)^5


Simplify:

(2x)^5: 32x^5

= 32768x^45 / 32x^5


Divide the numbers: 32768 / 32 = 1024

= 1024x^45 / x^5


Apply exponent rule: x^a / x^b = x^a - b

x^45 / x^5 = x^45 - 5

= 1024x^45 - 5


Subtract the numbers: 45 - 5 = 40

= 1024x^40

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4 - 5/8 = 3 3/8   answer


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Which function has exactly one real solution? A. f(x) = -4x2 + 9x B. f(x) = 2x2 + 4x – 5 C. f(x) = 6x2 + 11 D. f(x) = -3x2 + 30x
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{ \tt{f(x) =  - 4 {x}^{2} + 9x }}

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{ \tt{f(x) = x( - 4x + 9)}}

5 0
3 years ago
4. For each function, write the rule in vertex form and find the coordinates of the max/min point on its graph.
kakasveta [241]
'Vertex form', having just googled it, is another name for completing the square, which I have done extensively at school. This involved converting:
f(x) = ax^2 + bx + c --> f(x) = a(x-b)^2 + c

In the completed-square form, (b, c) are the co-ordinates of the vertex (which is the maximum/minimum point). So for part a:

- Here is the original
  f(x) = x^2 + 12x + 11

-  Halve the x-coefficient (the number before x) and use it as -b in the vertex form described above. You must then calculate the square of this number and minus it at the end because when you multiply it out, this is the surplus you will make along with x^2 + 12x:
  f(x) = (x + 6)^2  - 36 + 11

- Tidy this up by collecting the constant (just number) terms together:
  f(x) = (x + 6)^2 - 25

- Using the form a(x - b)^2 + c, we can work out that b = -6 (because -b = 6) and c = -25. This gives us the vertex (-6, -25) which is a minimum point because the graph is a positive quadratic, giving us the characteristing 'U' shape which has a bottom. If it were a negative quadratic (denoted by a negative x^2 coefficient), the vertex will be a maximum point because it has an 'n' shape instead.

- To solve the equation from here, make the function equal to zero:
  (x + 6)^2 - 25 = 0

- Then take 25 to the other side:
  (x + 6)^2 = 25

- Next, square-root both sides:
  x + 6 = <span>±5

- Rearrange to finish:
  x = -6 </span><span>± 5 = -1 or -11

- Therefore, the roots (solutions) to the equation x^2 + 12x + 11 = 0 are x = -1 or -11

This method will work the same for the other equations up there too, so I will leave them for you to do.

I hope this helps
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7 0
4 years ago
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