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3 years ago

Please help

Mathematics

1 answer:

poizon [28]3 years ago

7 0

Answer:

Step-by-step explanation:

4 people = 15 days

1 people = 15/4 = 3.75

so, 6 people = 3.75 × 6

= 22.5

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What does x equal if the circumference of a circle equals 113.04

Sveta_85 [38]

Circumference=2(pi)r or (pi)d
You know that Circumference=113.04
You know that the diameter=2x+4
Plug what you know into the equation and solve for x.
C =(pi) d
113.04=(pi)(2x+4)

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3 years ago

3(x+4)>12<br> can yall help me fr

Neko [114]

Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

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g A shopping center includes a grocery store and a drug store. One%E2%80%8B afternoon, a total of 200 people visited the shoppin

QveST [7]

Answer:

a) 179 people shopped at the grocery store or the drug store.

b) 21 people shopped at neither the grocery store nor the drug store

Step-by-step explanation:

I am going to treat these events as Venn sets.

I am going to say that:

Set A: Shopped at the grocery store

Set B: Shoped at the drug store.

121 shopped at the grocery store:

This means that $A = 121$

91 shopped at the drug store:

This means that $B = 91$

33 shopped at both businesses.

This means that $A \cap B = 33$

a) How many people shopped at the grocery store or the drug store?

This is

$A \cup B = A + B - (A \cap B)$

With the values given in the exercise.

$A \cup B = A + B - (A \cap B) = 121 + 91 - 33 = 179$

179 people shopped at the grocery store or the drug store.

b) How many people shopped at neither the grocery store nor the drug store?

179 of 200 shopped in at least one. So 200 - 179 = 21 shopped at neither.

21 people shopped at neither the grocery store nor the drug store

8 0

3 years ago

What is the range of the equation

a_sh-v [17]

The range of the equation is $y>2$

Explanation:

The given equation is $y=2(4)^{x+3}+2$

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

$y=2 \cdot 4^{x+3}+2$

This can be written as $y=2^{1+2(x+3)}+2$

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

$x=2^{1+2(y+3)}+2$

Solving for y, we get;

$x-2=2^{1+2(y+3)}$

Applying the log rule, if f(x) = g(x) then $\ln (f(x))=\ln (g(x))$ , then, we get;

$\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)$

Simplifying, we get;

$(1+2(y+3)) \ln (2)=\ln (x-2)$

Dividing both sides by $\ln (2)$ , we have;

$2 y+7=\frac{\ln (x-2)}{\ln (2)}$

Subtracting 7 from both sides of the equation, we have;

$2 y=\frac{\ln (x-2)}{\ln (2)}-7$

Dividing both sides by 2, we get;

$y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}$

Let us find the positive values for logs.

Thus, we have,;

$x-2>0$

$x>2$

The function domain is $x>2$

By combining the intervals, the range becomes $y>2$

Hence, the range of the equation is $y>2$

7 0

4 years ago