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2 years ago

In the x-y plane, what is the y- intercept of the graph of the equation y=6 (x-1/2) (x+3)

Mathematics

1 answer:

Ivenika [448]2 years ago

6 0

The y-intercept on the x-y plane is (0, -9).

<h3 /><h3>How to get the y-intercept?</h3>

To get the y-intercept we just need to evaluate in x = 0.

Here we have:

y = 6*(x - 1/2)*(x + 3)

Evaluating the given equation in x = 0 we get:

y = 6*(0 - 1/2)*(0 + 3) = -9

Then the y-intercept on the x-y plane is (0, -9).

If you want to learn more about y-intercepts:

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3 years ago

Can someone help me and explain step by step

Shkiper50 [21]

Answer: 5) r = 5, 8th term = -78,125

6) r = 5, 8th term = -312,500

7) r = 5, {1, 5, 25, 125, 625}

8) r = 5, {-4, -20, -100, -500, -2500}

<u>Step-by-step explanation:</u>

The explicit formula of a geometric sequence is: $a_n=a_1\cdot r^{n-1}$ , where;

n is the number of the term
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$5)\ a_n=-5^{n-1}\\.\qquad =-1\cdot 5^{n-1}\quad \rightarrow \quad a_1=-1\ and\ r=5\\\\a_8=-5^{8-1}\\.\quad =-5^7\\.\quad =-78,125\\\\\\6)\ a_n=-4\cdot 5^{n-1}\quad \rightarrow \quad a_1=-4\ and\ r=5\\\\a_8=-4\cdot 5^{8-1}\\.\quad =-4\cdot 78,125\\.\quad =-312,500$

$7)\ a_1=1\ and\ r=5\\.\quad a_2=1\cdot 5=\boxed{5}\\.\quad a_3=5\cdot 5=\boxed{25}\\.\quad a_4=25\cdot 5=\boxed{125}\\.\quad a_5=125\cdot 5=\boxed{625}\\\\\\\\8)\ a_1=-4\ and\ r=5\\.\quad a_2=-4\cdot 5=\boxed{-20}\\.\quad a_3=-20\cdot 5=\boxed{-100}\\.\quad a_4=-100\cdot 5=\boxed{-500}\\.\quad a_5=-500\cdot 5=\boxed{-2500}\\\\\\$

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3 years ago

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x + 40

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