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lisov135 [29]
3 years ago
14

What is a absolute value of this rational number negative two third

Mathematics
1 answer:
PIT_PIT [208]3 years ago
7 0
It is really 2/3 so the person that told u is correct
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Which of the following answer choices is an equation for the circle with a center of (-2, 3) and a radius of 3?
mamaluj [8]

Answer:

A

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = (- 2, 3) and r = 3 , then

(x + 2)² + (y - 3)² = 9 ← expand left side using FOIL

x² + 4x + 4 + y² - 6y + 9 = 9  ( subtract 9 from both sides )

x² + y² + 4x - 6y + 4 = 0 → A

5 0
3 years ago
If a=under root s(s-a)(s-b)(s-c) then the value of a, when a =3 b =4c = 5 and s =a+b+c by 2
kramer

Answer:

6

Step-by-step explanation:

Here it's given that ,

\sf\red{\longrightarrow} A=\sqrt{s(s-a)(s-b)(s-c)}

Also ,

\sf\red{\longrightarrow} s =\dfrac{a+b+c}{2}

And we need to find out the value of A , when

  • a = 3
  • b = 4
  • c = 5

So , on substituting the respective values to find s we have ,

\sf\red{\longrightarrow} s =\dfrac{3+4+5}{2}=\dfrac{12}{2}=\bf{6}

Now let's find out A as ,

\sf\red{\longrightarrow} A = \sqrt{6(6-3)(6-4)(6-5)} \\

\sf\red{\longrightarrow}A =\sqrt{6 * 3 * 2 * 1}\\

\sf\red{\longrightarrow} A = \sqrt{3^2 * 2^2 *1^2}\\

\sf\red{\longrightarrow}A = 3*2\\

\sf\red{\longrightarrow}\boxed{\qquad \blue{\bf A = 6 \qquad}}

7 0
2 years ago
-10x+45 find x when x =15
leonid [27]
Your answer is -105 pal
3 0
3 years ago
Read 2 more answers
Can you answer this please 20 and brainlest for correct answer points I forgot how to do it I’m in middle school
leonid [27]

Answer:

6 2/3 or 20/3

Step-by-step explanation:

Brainliest pls?

5 0
3 years ago
Read 2 more answers
How many different three-letter initials with none of the letters repeated can people have?
viva [34]
This is a probablity question

there are 3 slots, 26 letters of the alphabet

so in the first slot, we have 26 possible letters
2nd slot, we have 25 possible letters (we used one for the first slot)
3rd slot, we have 24 possible letters, (we used 2 for first and 2nd slot)

so in total, we have 26*25*24 or 15600 different 3 letter initials with no repeated letters
3 0
3 years ago
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