in a US gallon, there are approximately 3.79 Liters, in a Liter there are 1000 milliLiters, so 3.79 Liters is then 3.79 * 1000 milliLiters, namely 3790 milliliters.
since a gallon is then approximately 3790 mL, how many times does 5mL go in to 3790? 3790 ÷ 5 = 758.
since the child uses 5mL in 1 day, then 758 times that is 758 days.
Answer:
-1/2
Step-by-step explanation:
-5/6 × 3/5
numerator: -5 × 3 = -15
denominator: 6 × 5= 30
-15÷30= -1/2
Answer:
x=3 meters
Step-by-step explanation:
step 1
Find the area of the rectangular pool

we have

substitute

step 2
Find the area of rectangular pool including the area of the walkway
Let
x ----> the width of the walkway
we have

substitute

step 3
Find the area of the walkway
To find out the area of the walkway subtract the area of the pool from the area of rectangular pool including the area of the walkway
so

step 4
Find the value of x if the area of the walkway equal the area of the pool
so

Solve for x

Solve the quadratic equation by graphing
The solution is x=3 meters
see the attached figure
Y = -0.4x
1) It is a straight line
2) I passes through the origin (0,0), because the y-intercpet is 0.
3) The slope is negative, so it passes throuh II and III quadrants
4) The magnitude of the slope = 0.4
4) The angle of the line with the negative side of the x-axis is that whose tan is 0.4 => angle = 21.8 °
With all that information you can identify the graph, given that you didn't include the options.
Answer:
Step-by-step explanation:
a. This is a decay function, since the final value (A) gets smaller and smaller as the days pass by.
b. The bacteria is decreasing by 75% per day exponentially.
c. In order to calculate the amount of bacteria in a week we simply substitute the variable t for 7 (7 days in a week) and solve for A
A = 200(0.75)^7
A = 26.7 bacteria after 1 week
d. In order to calculate this we need to substitute the variable A with 100 and solve for t
100 = 200(0.75)^t ... divide both side by 200
0.5 = 0.75^t
= t
2.4 = t
It will be half the initial amount after 2.4 days.