What is the slope-intercept form of the equation of the line containing the points (−2, 4) and (6, 0)?
1 answer:
The slope-intercept form of the equation of the line containing the points (−2, 4) and (6, 0) will be y =0.5 x+ 5.
<h3>What is the slope?</h3>A numerical assessment of a line's angle relative to the ground is known as the slope.
The inclination of any line, ray, or line segment is the fraction of the perpendicular to the horizontal distance between any two positions on it.
The slope of the line is found as;
The standard line equation is;
y-y₁=m(x-x₁)
Hence, the slope-intercept form of the equation of the line containing the points (−2, 4) and (6, 0) will be y =0.5 x+ 5.
To learn more about the slope, refer to the link;
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Answer with Step-by-step explanation:
We are given that function f(x) which is quadratic function.
x -intercept of function f(x) at (-1,0) and (-3,0)
x-Intercept of f means zeroes of f
x=-1 and x=-3
Range of f =[-4,)
g(x)=
Therefore, x-intercept of g(x) at (-1,0) and (-3,0).
Substitute x=-2
By comparing with the equation of parabola
Where vertex=(h,k)
We get vertex of g(x)=(-2,-2)
Range of g(x)=[-2,)
Zeroes of f and g are same .
But range of f and g are different.
Range of f contains -3 and -4 but range of g does not contain -3 and -4.
f and g are both quadratic functions.
