Answer: The ratios are both identical. (Choice A)
Why does this answer work?
Well let's refer to the diagram below.
Angle x has side 12 opposite it and the hypotenuse is 13.
This means sin(x) = opposite/hypotenuse = 12/13
Also, angle y has side 12 adjacent to it, meaning,
cos(y) = adjacent/hypotenuse = 12/13
Both trig ratios result in 12/13 and we can say sin(x) = cos(y)
One last thing to notice is that x+y = 90
In other words, if x+y = 90, then sin(x) = cos(y)
Phrased a slightly different way: if x+y = 90, then sin(y) = cos(x)
This answers I believe is 30 ft
Answer:
+1 and -1
Step-by-step explanation:
The function in this problem is:
First of all, we have to define the domain of the function, which is the set of values of x for which the function is defined.
In order to find the domain, we have to require that the denominator is different from zero, so
which means:
So the domain is all values of x, except from 4 and -7.
Now we can solve the problem and find the zeros of the function. The zeros can be found by requiring that the numerator is equal to zero, so:
This is verified if either one of the two factors is equal to zero, therefore:
and
We see that both values are part of the domain, so they are acceptable values: so the zeros of the function are +1 and -1.
I'm not sure if this is right... ( if you search up the internet... it tells you the formula and you just have to fill in the missing pieces like the length, base, and height.) I got... 207.23... Good luck on finding the right answer!
The test score for a class are shown. What is the average test score? 79,80,92,92,81,100,88,98,71,100,91,90
Oksanka [162]
Answer:
The average score is equal to 88.5
Step-by-step explanation:
we know that
An average test score is the sum of all the scores on an assessment divided by the number of test-takers.
so
The sum is equal to
![Sum=[79+80+92+92+81+100+88+98+71+100+91+90]=1,062](https://tex.z-dn.net/?f=Sum%3D%5B79%2B80%2B92%2B92%2B81%2B100%2B88%2B98%2B71%2B100%2B91%2B90%5D%3D1%2C062)
The number of test-takers is n=12
The average score is equal to
substitute
