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fgiga [73]
3 years ago
12

Winston found $3.75 for in change on the beach with

Mathematics
1 answer:
Citrus2011 [14]3 years ago
5 0

Answer:

Winston can find $1.125 dollars every 1 hour.

Step-by-step explanation:

I got this by dividing 3.75 by 3 1/3.

3.75 ÷ 3 1/3 = 1.125

Hope this helps! :)

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Note that WXYZ has vertices W(-1, 2), X(-5, 7), y(-1, -2), and Z (3, -7).
svp [43]

a. Slope of WZ = -2.25; Slope of WX = 5

b. WZ = √97; WX = √41

c. WXYZ is not a <em>rectangle, rhombus, nor a square</em>. We can conclude that: <em>D. WXYZ is none of these</em>.

<h3>Slope of a Segment</h3>

Slope = change in y/change in x

Given:

W(-1, 2), X(-5, 7), Y(-1, -2), and Z (3, -7)

a. Slope of WZ and slope of WX:

Slope of WZ = (-7 - 2)/(3 -(-1)) = -2.25

Slope of WX = (7 - 2)/(-1 -(-1)) = 5

b. Use distance formula, d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}, to find WZ and WX:

WZ = \sqrt{(3 - (-1))^2 + (-7 - 2)^2}\\\\\mathbf{WZ = \sqrt{97} }

WX = \sqrt{(-5 -(-1))^2 + (7 - 2)^2}\\\\\mathbf{WX = \sqrt{41} }

c. The quadrilateral WXYZ have adjacent sides that are not perpendicular to each other and have different slopes and different lengths, so therefore, WXYZ is not a rectangle, rhombus, nor a square. We can conclude that: <em>D. WXYZ is none of these</em>.

Learn more about slopes on:

brainly.com/question/3493733

5 0
3 years ago
6r + 7 = 13 + 7r what is r
kumpel [21]

Answer:

6r+7=13+7r

6r+7=7r+13

6r+7−7r=7r+13−7r

−r+7=13

−r+7−7=13−7

−r=6

\frac{-r}{-1} = \frac{6}{-1}

r=−6

Step-by-step explanation:

:) This is the answer

6 0
3 years ago
Read 2 more answers
Write a word phrase to represent the numerical expression for 4+[27-10]
vlabodo [156]
Four plus the absolute value of twenty-seven minus ten
3 0
3 years ago
Can’t solve this problem
Georgia [21]
The answer is 5 units. the top is 10, and x is half of that
5 0
3 years ago
Suppose James randomly draws a card from a standard deck of 52 cards. He then places it back into the deck and draws a second ca
qwelly [4]

Answer:

1.92%

Step-by-step explanation:

The probability for first case, picking a queen out of deck, will be:

\frac{4}{52}

as there will be 4 queens in a deck, one of each suit.

For the second pick, the probability of picking a diamond card, will be:

\frac{13}{52}

here the total will remain 52 as he has replaced the first card and not kept it aside and there will be 13 cards in diamond suit (including the three face cards).

Thus the net probability for both cases will be:

P = \frac{4}{52}  * \frac{13}{52}\\ P = \frac{1}{52}\\ P = 0.01923\\P = 1.923\%\\\\P = 1.92\%

Thus total probability for the combined two cases will be 1.92%

7 0
3 years ago
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