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1 year ago

A student ran a distance of 3 miles each day for 5 days. Then the student ran a distance of 4 miles each day for the next 5 days

1 answer:

azamat1 year ago

8 0

The total distance was 35 miles. Why? Well, see below:

The student ran 3 miles each day for 5 days. That can be representative of:

Day 1: 3 miles
Day 2: 3 miles
Day 3: 3 miles
Day 4: 3 miles
Day 5: 3 miles

Adding these values together, we will find that the student ran a total of 15 miles in the first five days.

As for the next set of 5 days, we can represent this by modeling like we did above:

Day 6: 4 miles
Day 7: 4 miles
Day 8: 4 miles
Day 9: 4 miles
Day 10: 4 miles

Adding the values from the second set of days, we will find that in days 6-10, the student ran a total of 20 miles.

We can add the total values together to identify the total distance the student ran during these 10 days.

15 + 20 = 35 total miles

Hence, the student ran a total of 35 miles over the course of 10 days. If you need help, let me know and I will go ally assist you.

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Answer:

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3 years ago

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2 years ago

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Gekata [30.6K]

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3 years ago

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The line l passes through the point P = (1,-1,1) and has direction vector d = [2,3,1]. Determine whether l and the plane 4x-y+5z

suter [353]

Hello :
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3 0

3 years ago

A school dance committee has 14 volunteers. Each dance requires 3 volunteers at the door, 5 volunteers on the floor, and 6 float

siniylev [52]

There are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned from 14 volunteers.

Given that a school dance committee has 14 volunteers and each dance requires 3 volunteers at the door, 5 volunteers on the floor and 6 on floaters.

We are required to find the number of ways in which the volunteers can be assigned.

Combinations means finding the ways in which the things can be choosed to make a new thing or to do something else.

n $C_{r}$ =n!/r!(n-r)!

Number of ways in which the volunteers can be assigned is equal to the following:

Since 2 have not been assigned so left over volunteers are 14-2=12 volunteers.

Number of ways =14 $C_{12}$

=14!/12!(14-12)!

=14!/12!*2!

=14*13/2*1

=91 ways

Hence there are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned.

Learn more about combinations at brainly.com/question/11732255

#SPJ1

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2 years ago