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lidiya [134]
3 years ago
5

The line l passes through the point P = (1,-1,1) and has direction vector d = [2,3,1]. Determine whether l and the plane 4x-y+5z

= 0 are parallel, perpendicular, or neither.
Mathematics
1 answer:
suter [353]3 years ago
3 0
Hello : 
the normal vector of the plane is : d' = [4,-1,5]...(vector  perpendicular to the plane)<span>
d </span><span>⊥ d' because : (4)(2)+(-1)(3)+(5)(1)=0
</span>the line is perpendicular to the plane .
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Which quotient matches the description of solving with partial quotients for 240÷15
Illusion [34]

Answer:

C. 16

Step-by-step explanation:

240/15

Step one: 10x15= 150

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Partial quotient: 10

Step two: 6x15= 90

                 90-90= 0

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Describe the given set with a single equation or with a pair of equations. The plane through the point (7 comma 6 comma negative
devlian [24]

Answer:

(a) Along the xy-plane,

7x + 6y = 0

(b) Along the yz-plan,

2y - 3z = 0

(c) Along the xz-plane,

7x - 3z = 0

Step-by-step explanation:

To describe the given set.

Given the plane (7, 6, -3),

We have the equation as

7x + 6y - 3z = 0

(a) Along the xy-plane, z = 0, and we have

7x + 6y = 0

(b) Along the yz-plan, x = 0, and we have

6y - 3z = 0

Or

2y - 3z = 0

(c) Along the xz-plane, y = 0, and we have

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8 0
3 years ago
Ashley adds Polynomial A and B together:
icang [17]

Answer:

coefficient of x: 2

coefficient of y: 3

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Step-by-step explanation:

To solve this problem, first we need to sum the polynomials A and B, then we need to check the coefficients of x, y and z.

The sum of the polynomials is:

A + B = 5z + 4x^2 - 6y + 2 + 2x + 9y - 12z - 2

A + B = 4x^2 + 2x + 3y - 7z

So, the coefficients are:

coefficient of x^2: 4

coefficient of x: 2

coefficient of y: 3

coefficient of z: -7

3 0
3 years ago
Read 2 more answers
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