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worty [1.4K]
2 years ago
12

Find the solution of this system of equations. Separate the x- and y-values with a comma. x - 4y = 9 and x - y = -9

Mathematics
1 answer:
Cerrena [4.2K]2 years ago
4 0
X - 4y =  9 ------- (1)
x - y = -9 ---------(2)

(2) - (1):
-y - (-4y) = -9 - 9
-y + 4y = -18
3y = -18
y = -6 . -------- sub into (2)

x - (-6) = -9
x + 6 = -9
x = -9 - 6
x = -15

Ans: x = -15, y = -6

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Fynjy0 [20]

Answer:

The equation showing this situation is  D=b^2-4ac=0

Step-by-step explanation:

Given : A quadratic equation of the form ax^2 + bx + c=0  has one real number solution.

To find : Which could be the equation?  

Solution :

A quadratic equation in form ax^2+bx+c=0 has a solution x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} called a quadratic formula  in which the roots are one real,two real or no real is determine by discriminant factor.

Discriminant is defined as to determine the number of roots in a quadratic equitation has following rules :

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2) If D=b^2-4ac=0 there are one real roots.

3) If D=b^2-4ac there are no real roots.

According to question,

A quadratic equation of the form ax^2 + bx + c=0  has one real number solution.

So, The equation showing this situation is  D=b^2-4ac=0

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