2 years ago

The product of 2 more than 3 times a number and 6 less than 4 times the number (z)

Mathematics

1 answer:

Rom4ik [11]2 years ago

7 0

Answer:

$12z^{2} -10z -12$

Step-by-step explanation:

Let the number be z

2 more than 3 times z ==> 3z + 2

6 less than 4 times z ==> 4z - 6

Product of the above two is
$(3z + 2) (4z - 6) \\= (3z)(4z) + (3z)(-6) + (4z)(2) + (2)(-6)\\= 12z^{2} -18z + 8z - 12\\= 12z^{2} -10z -12$

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