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3 years ago

15

The range is the set of

1 answer:

slavikrds [6]3 years ago

7 0

Answer:The range of a set of data is the difference between the highest and lowest values in the set.

Step-by-step explanation: The range of a set of data is the difference between the highest and lowest values in the set. To find the range, first order the data from least to greatest. Then subtract the smallest value from the largest value in the set.

Hope this helps :)

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Combine the following sets of terms.

DanielleElmas [232]

Let's simplify step-by-step To understand :)

3x2−7x−(x2+3x−9)

Distribute the Negative Sign:

=3x2−7x+−1(x2+3x−9)

=3x2+−7x+−1x2+−1(3x)+(−1)(−9)

=3x2+−7x+−x2+−3x+9

Combine Like Terms:)

=3x2+−7x+−x2+−3x+9

=(3x2+−x2)+(−7x+−3x)+(9)

=2x2+−10x+9

Answer :)

=2x2−10x+9

HOPE THIS HELPS

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Segment PQ has a midpoint of E. If PE=4x-3 and 6x+2, what is the value of x ?

topjm [15]

Answer:

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Step-by-step explanation:

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3 years ago

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RSB [31]

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Svetlanka [38]

Answer:

$\sqrt[]{\frac{x+8}{4}}-3$

Step-by-step explanation:

$g(x)=4(x+3)^2-8$

First rewrite $g(x)$ as y

$y=4(x+3)^2-8$

Now swap y and x

$x=4(y+3)^2-8$

Add 8 on both sides.

$x+8=4(y+3)^2-8+8$

$x+8=4(y+3)^2$

Divide by 4.

$\frac{x+8}{4} =\frac{4(y+3)^2}{4}$

$\frac{x+8}{4}=(y+3)^2$

Extract the square root on both sides.

$\sqrt[]{\frac{x+8}{4}}=\sqrt[]{(y+3)^2}$

$\sqrt[]{\frac{x+8}{4}}=y+3$

Subtract 3 on both sides.

$\sqrt[]{\frac{x+8}{4}}-3=y+3-3$

$\sqrt[]{\frac{x+8}{4}}-3=y$

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2 years ago

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Each ticket cost 18$

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