Answer:
The first graph (top-left) is the correct graph.
Please, also check the attached graph.
Step-by-step explanation:
Given the function

First, we should determine the x and y-intercepts.
Determining the y-intercept:
We know that the value of the y-intercept can be determined by setting x = 0 and determining the corresponding value of y.
Thus,
substitute x = 0 in the function
y = lnx
y = ln(0)
y = undefined
Therefore, at x = 0, the value of y becomes undefined.
Hence, None is the y-intercept.
Determining the x-intercept:
We know that the value of the x-intercept can be determined by setting y = 0 and determining the corresponding value of x.
Thus,
substitute y = 0 in the function
0 = ln(x)
Flipe the equation
ln(x) = 0
Solve algorithm
ln(x) = 0
Take exponent of both sides



Thus, the point of x-intercept is: (0, 1)
<u>Conclusion:</u>
Now, if we carefully check the graph options, we can easily figure out that the first graph (top-left) correctly displays the x and y-intercepts.
It is clear from the graph that:
at x = 0, y is heading towards -ve infinity.
at y = 0, x = 1
Therefore, the first graph (top-left) is the correct graph.
Please, also check the attached graph.