Answer:
Input Data :
Point 1(xA,yA)(xA,yA) = (4, 3)
Point 2(xB,yB)(xB,yB) = (3, -2)
Objective :
Find the distance between two given points on a line?
Formula :
Distance between two points = √(xB−xA)2+(yB−yA)2(xB-xA)2+(yB-yA)2
Solution :
Distance between two points = √(3−4)2+(−2−3)2(3-4)2+(-2-3)2
= √(−1)2+(−5)2(-1)2+(-5)2
= √1+251+25
= √2626 = 5.099
Distance between points (4, 3) and (3, -2) is 5.099
Step-by-step explanation:
this photo is correct answer of this question.
Answer:
I think x=8
Step-by-step explanation:
5(x+7)+15=90
90 because it's a 90 degree angle
5x+35+15=90
5x+50=90
5x=40
x=8
11:10
subtract 20 minutes from 12:00 then subtract 30 minutes from what you get from that
Answer:
2. (1.5, 1.5)
Step-by-step explanation:
midpoint = (x1+x2)/2 , (y1+y2)/2
A = (-3,-3) and B = (6,6)
midpoint = (-3+6)/2, (-3+6)/2
= 3/2 , 3/2