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2 years ago

12

there are two hydrogen atoms and one oxygen atom in a water molecule. complete the table, and graph the ordered pairs on the coo

rdinate graph.

1 answer:

max2010maxim [7]2 years ago

6 0

Answer:

______ allows data to be transmitted by the computer in ahu-man-of riendly from

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Solve the system of equations.

Llana [10]

2x + 3y = 13

–6x + 4y = 0

multiply the first equation by 3

6x +9y = 39

then add the 2nd equation to the first

6x +9y = 39

–6x + 4y = 0

-------------------

13y = 39

divide by 13

y =3

now take an equation and solve for x by substituting in y

2x +3y =13

2x +3(3) =13

2x+9 =13

subtract 9 from each side

2x =4

divide by 2

x=2

Answer (2,3)

Choice A

4 0

3 years ago

2.The number of grams A of a certain radioactive substance present at time, in yearsfrom the present, t is given by the formulaA

professor190 [17]

Answer:

Given that,

The number of grams A of a certain radioactive substance present at time, in years

from the present, t is given by the formula

$A=45e^{-0.0045(t)}$

a) To find the initial amount of this substance

At t=0, we get

$A=45e^{-0.0045(0)}$ $A=45e^0$

We know that e^0=1 ( anything to the power zero is 1)

we get,

$A=45$

The initial amount of the substance is 45 grams

b)To find thehalf-life of this substance

To find t when the substance becames half the amount.

A=45/2

Substitute this we get,

$\frac{45}{2}=45e^{-0.0045(t)}$

$\frac{1}{2}=e^{-0.0045(t)}$

Taking natural logarithm on both sides we get,

$\ln (\frac{1}{2})=-0.0045(t)^{}$ $(-1)\ln (\frac{1}{2})=0.0045(t)$ $\ln (\frac{1}{2})^{-1}=0.0045(t)$ $\ln (2)=0.0045(t)$ $0.6931=0.0045(t)$ $t=\frac{0.6931}{0.0045}$ $t=154.02$

Half-life of this substance is 154.02

c) To find the amount of substance will be present around in 2500 years

Put t=2500

we get,

$A=45e^{-0.0045(2500)}$ $A=45e^{-11.25}$ $A=45\times0.000013=0.000585$ $A=0.000585$

The amount of substance will be present around in 2500 years is 0.000585 grams

4 0

7 months ago

Which statement is true?

NeTakaya

D. Hope this helps :))

7 0

3 years ago

20. Joshua sold a batch of tickets for carnival rides. The ratio of adult

nikitadnepr [17]

Step-by-step explanation:

a = original number of adult tickets

c = original number of child tickets

a/c = 2/5

a = 2c/5

(a+70)/(c+300) = 1/3

(2c/5 + 70)/(c + 300) = 1/3

2c/5 + 70 = (c + 300)/3

2c + 350 = 5(c + 300)/3

6c + 1050 = 5(c + 300) = 5c + 1500

c = 450

a = 2c/5 = 2×450/5 = 2×90 = 180

Joshua sold therefore in total

180 + 70 = 250 adult tickets.

and by the way

450 + 300 = 750 child tickets.

6 0

2 years ago

12) PLS HELP ASAP<br><br><br>BRAINLIEST AND 10 + POINTS :)

puteri [66]

Answer:

the first one

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers