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2 years ago

Help me please im stuck here

Mathematics

1 answer:

natita [175]2 years ago

7 0

The reciprocal relationship of the graph is graph (a)

<h3>How to determine the reciprocal relationship? </h3>

The reciprocal relationship implies that:

The x and the y axes are swapped.

When the x and the y axes are swapped, the value on both axes swap their positions

For the given graph, the reciprocal relationship is graph (a)

This is shown in the attached graph

Read more about reciprocal relationship at:

brainly.com/question/2321596

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A) The hypotenuse of a right angled triangle is 15 cm. Taking the

Anastasy [175]

a) By Pythagoras theorem , h^2 is = a^2 + b^2 where a is the hypotenuse and a and b are the legs.

=) 15^2 = x^2 + y^2

That is the relation

b) area of triangle = 1/2 x height x base

=) 1/2 * x * y = 30

=) xy = 15cm

3 0

3 years ago

4. will give brainliest

saul85 [17]

The equation of the ellipse in <em>standard</em> form is (x + 3)² / 100 + (y - 2)² / 64 = 1. (Correct choice: B)

<h3>What is the equation of the ellipse associated with the coordinates of the foci?</h3>

By <em>analytical</em> geometry we know that foci are along the <em>major</em> axis of ellipses and beside the statement we find that such axis is parallel to the x-axis of Cartesian plane. Then, the <em>standard</em> form of the equation of the ellipse is of the following form:

(x - h)² / a² + (y - k)² / b² = 1, where a > b (1)

Where:

a - Length of the major semiaxis.
b - Length of the minor semiaxis.

Now, we proceed to find the vertex and the lengths of the semiaxes:

a = 10 units.

b = 8 units.

Vertex

V(x, y) = 0.5 · F₁(x, y) + 0.5 · F₂(x, y)

V(x, y) = 0.5 · (3, 2) + 0.5 · (- 9, 2)

V(x, y) = (1.5, 1) + (- 4.5, 1)

V(x, y) = (- 3, 2)

The equation of the ellipse in <em>standard</em> form is (x + 3)² / 100 + (y - 2)² / 64 = 1. (Correct choice: B)

To learn more on ellipses: brainly.com/question/14281133

#SPJ1

8 0

2 years ago

Each of the line segments in the word MATH are numbered in the graph below. Find the slope (as a ratio of rise over run) of each

emmasim [6.3K]

Answer/Step-by-step explanation:

7. Line 1 = undefined.

Slope of a vertical line is always undefined. The run is zero as x-coordinate remains the same.

8. Line 2 = $\frac{4}{3}$

$slope = \frac{y_2 - y_1}{x_2 - x_1}$

$slope = \frac{8 - 4}{-5 -(-8)}$

$slope = \frac{8 - 4}{-5 + 8}$

$slope = \frac{4}{3}$

9. Line 3 = $\frac{4}{3}$

$slope = \frac{y_2 - y_1}{x_2 - x_1}$

$slope = \frac{8 - 4}{-2 -(-5)}$

$slope = \frac{8 - 4}{-2 + 5}$

$slope = \frac{4}{3}$

10. Line 4 = undefined (slope of a vertical line is always undefined)

11. Line 5 = $\frac{7}{3}$

$slope = \frac{y_2 - y_1}{x_2 - x_1}$

$slope = \frac{8 - 1}{5 - 2}$

$slope = \frac{7}{3}$

12. Line 6 = $-\frac{7}{3}$

$slope = \frac{y_2 - y_1}{x_2 - x_1}$

$slope = \frac{8 - 1}{5 - 8}$

$slope = \frac{7}{-3}$

$slope = -\frac{7}{3}$

13. Line 7 = 0

An horizontal line has no rise.

14. Line 8 = 0 (slope of horizontal line is always zero)

15. Line 9 = undefined (slope of a vertical line is always undefined)

16. Line 10 = undefined (slope of a vertical line is always undefined)

17. Line 11 = 0 (slope of horizontal line is always zero)

18. Line 12 = undefined (slope of a vertical line is always undefined)

5 0

3 years ago

Find the perimeter of a rectangle whose length is 15 cm and length of one diagonal is 17cm

Ulleksa [173]

Answer:

Step-by-step explanation:

first ,we use the Pythagorean theorem to determine the width:

width = √(17^2-15^2) = 8

then

perimeter = 2(width+lengt) = 2(8 + 15) = 2×23 = 46

6 0

4 years ago

three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal

Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

= x + x + (x + $\frac{6}{5}$ ) = $\frac{27}{4}$

= 3x + $\frac{6}{5}$ = $\frac{27}{4}$

= 3x = $\frac{27}{4}$ - $\frac{6}{5}$

( let's take the LCM of 4 and 5 = 20

= 3x = $\frac{135}{20}$ - $\frac{24}{20}$

= 3x = $\frac{111}{20}$

= x = $\frac{111}{20}$ ÷ $\frac{3}{1}$ = $\frac{111}{20}$ × $\frac{1}{3}$ = $\frac{37}{20}$

So, the weight of the equal bags are $\frac{37}{20}$ and the weight of the third bag ( heavy one ) is $\frac{37}{20}$ + $\frac{6}{5}$ = $\frac{37}{20}$ + $\frac{24}{20}$ = $\frac{61}{20}$

1st bag = $\frac{37}{20}$ kg

2nd bag = $\frac{37}{20}$ kg

3rd bag = $\frac{61}{20}$ kg

Hope it helps...

7 0

3 years ago