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1 year ago

Help me please im stuck here

Mathematics

1 answer:

natita [175]1 year ago

7 0

The reciprocal relationship of the graph is graph (a)

<h3>How to determine the reciprocal relationship? </h3>

The reciprocal relationship implies that:

The x and the y axes are swapped.

When the x and the y axes are swapped, the value on both axes swap their positions

For the given graph, the reciprocal relationship is graph (a)

This is shown in the attached graph

Read more about reciprocal relationship at:

brainly.com/question/2321596

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Construct a rhombus whose diagonals are 6.2cm 8.4cm long

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Answer:

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3 years ago

Find an equation of the sphere which contains points A(1, 3, 2) and B(4, 3, 7) and the distance between A and B is equal to the

Marina86 [1]

Answer:

The answer is 8.5=(x-2.5)^2+(y-3)^2+(z-4.5)^2

Step-by-step explanation:

First we need to find diameter of the sphere. The distance point A and point B is:

$d=\sqrt{(4-1)^2+(3-3)^2+(7-2)^2} \\d=\sqrt{3^2+0^2+5^2} \\d=\sqrt{34} \\d=5.83$

d/2=r=2.92

radius of the sphere is 2.92 units

and the center of the sphere is:

C=((4+1)/2,(3+3)/2,(7+2)/2)

C=(2.5,3,4.5)

We can write the equation of the sphere as:

$r^2=(x-2.5)^2+(y-3)^2+(z-4.5)^2\\8.5=(x-2.5)^2+(y-3)^2+(z-4.5)^2$

4 0

3 years ago

If it takes you 20 minutes to hike a distance of 1 mile, how fast are you walking in miles per hour

Leni [432]

Answer:

1.60934 per hour

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4 0

3 years ago

Read 2 more answers

Which way shows one way you can decompose 15 to find 42 x 15?

soldier1979 [14.2K]

Answer:

42 * 10 + 42 * 5

which agrees with the third option (C) shown on the list of possible answers

Step-by-step explanation:

Notice that using distributive property we can write:

42 * 15 = 42 (10 + 5) = 42 * 10 + 42 * 5

which agrees with the third option (C) shown on the list of possible answers.

5 0

2 years ago

X2 - 6x + 12 and y = 2x - 4, algebraically are

olga_2 [115]

The solution is (4, 4)

Solution:

Given system of equations are:

$y = x^2 - 6x + 12 ------ eqn\ 1\\\\y = 2x - 4 ---------- eqn\ 2$

Substitute eqn 2 in eqn 1

$x^2 - 6x + 12 = 2x - 4$

Make the right side of equation 0

$x^2 - 6x + 12 - 2x + 4 = 0\\\\x^2 -8x + 16 = 0$

Solve by quadratic equation

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=-8,\:c=16:\\\\x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}\\\\x=\frac{-\left(-8\right)\pm \sqrt{0}}{2\cdot \:1}\\\\x = \frac{8}{2}\\\\x = 4$

Substitute x = 4 in eqn 2

y = 2(4) - 4

y = 8 - 4

y = 4

Thus solution is (4, 4)

5 0

2 years ago