<span>You are given the waiting times between a subway departure schedule and the arrival of a passenger that are uniformly distributed between 0 and 6 minutes. You are asked to find the probability that a randomly selected passenger has a waiting time greater than 3.25 minutes.
Le us denote P as the probability that the randomly selected passenger has a waiting time greater than 3.25 minutes.
P = (length of the shaded region) x (height of the shaded region)
P = (6 - 3.25) * (0.167)
P = 2.75 * 0.167
P = 0.40915
P = 0.41</span><span />
the answer of 2x +y = 20 ; 6x -5y =12
{ explained in image}
Answer:
18.75 pounds, 1.75 pounds collected less
Step-by-step explanation:
3.75 pounds = 1 month
20.5 pounds need to be collected
5 months
3.75 x 5 = 18.75
20.5 - 18.75 = 1.75
