Answer:
1) C
2) A
3) E
Step-by-step explanation:
Answer:
Part 1) The exact solutions are
and
Part 2) (1.79, 8.58)
Step-by-step explanation:
we have
----> equation A
----> equation B
we know that
When solving the system of equations by graphing, the solution of the system is the intersection points both graphs
<em>Find the exact solutions of the system</em>
equate equation A and equation B

The formula to solve a quadratic equation of the form
is equal to
in this problem we have
so
substitute in the formula
so
The solutions are
<em>Find the values of y</em>
<em>First solution</em>
For 


The first solution is the point
<em>Second solution</em>
For 


The second solution is the point
Round to the nearest hundredth
<em>First solution </em>
-----> 
-----> 
see the attached figure to better understand the problem
Answer:
100㏑²
Step-by-step explanation;
first of all you find the base using the pythagoras theorem
that is, √13² - 12² =√25 = 5
so 5 is the base of the right angle in the big isoceles triangle
so the base of the isoceles triangle is 10 [5 + 5]
so for the first triangle the area is 60㏑²
the second triangle is 40㏑²
therefore 60 + 40 = 100㏑²
Let ∠RTS=∠RST = a (say)
∠QUA=∠QSU= b(say)
then we know , at point S, a+40+b=180. so, a+b=140 we'll use this later.
consider trianglePQR, ∠P+∠Q+∠R=180
i.e.P+(180-2b)+(180-2a)=180
P+180+180-2(a+b)=180 ⇒P+180-2(a+b)=0 ⇒P=2(140)- 180=280-180=100
hence,answer is E
Answer:
C) 6
Step-by-step explanation:
I converted the equation into slope-intercept form and then identified the y-intercept.

C should be the correct answer.
Hope this helps.