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laiz [17]
3 years ago
5

(Write As Unit Rate) 12 Meters In 28 Seconds

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
8 0

Answer:

2.3 repeating

Step-by-step explanation:

12/28=1/x

12x=28

divide both sides by 12

x=2.3 repeating

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A cube is cut in to three parts by vertical slices find the volume of the shaded area The length and width of original is 20 cm
Anni [7]

Answer:

4000 cm^3

Step-by-step explanation:

Note that no image was attached for reference purposes

Step one:

We are given that the original length and width of the cube is 20cm

if the cut part is 10cm

hence the dimension of the cut part is

lenght = 20cm

Width= 20cm

Hieght= 10cm

Step two:

the volume of the cut part will be

Volume= 20*20*10

Volume= 4000 cm^3

7 0
3 years ago
A particle is projected with a velocity of <img src="https://tex.z-dn.net/?f=40ms%5E-%5E1" id="TexFormula1" title="40ms^-^1" alt
Katena32 [7]

Answer:

2\sqrt{55}\text{ m/s or }\approx 14.8\text{m/s}

Step-by-step explanation:

The vertical component of the initial launch can be found using basic trigonometry. In any right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. Let the vertical component at launch be y. The magnitude of 40\text{ m/s} will be the hypotenuse, and the relevant angle is the angle to the horizontal at launch. Since we're given that the angle of elevation is 60^{\circ}, we have:

\sin 60^{\circ}=\frac{y}{40},\\y=40\sin 60^{\circ},\\y=20\sqrt{3}(Recall that \sin 60^{\circ}=\frac{\sqrt{3}}{2})

Now that we've found the vertical component of the velocity and launch, we can use kinematics equation v_f^2=v_i^2+2a\Delta y to solve this problem, where v_f/v_i is final and initial velocity, respectively, a is acceleration, and \Delta y is distance travelled. The only acceleration is acceleration due to gravity, which is approximately 9.8\:\mathrm{m/s^2}. However, since the projectile is moving up and gravity is pulling down, acceleration should be negative, represent the direction of the acceleration.

What we know:

  • v_i=20\sqrt{3}\text{ m/s}
  • a=-9.8\:\mathrm{m/s^2}
  • \Delta y =50\text{ m}

Solving for v_f:

v_f^2=(20\sqrt{3})^2+2(-9.8)(50),\\v_f^2=1200-980,\\v_f^2=220,\\v_f=\sqrt{220}=\boxed{2\sqrt{55}\text{ m/s}}

3 0
3 years ago
0.09 is 10 times as much as ?
ANEK [815]
To find out the answer we divide 0.09 by 10: 0.09÷10=0.009. Therefore, 0.09 is 10 times as much as 0.009.
5 0
3 years ago
Read 2 more answers
The cost of raincoat is rs 400 and VAT is rs 40 find the rate of VAT​
DaniilM [7]

Divide vat by price

40/400 = 0.1

Multiply by 100

0.1 x 100 = 10%

Rate of vat is 10%

5 0
3 years ago
A fraternity charged $2.00 admission for dudes and $1.00 admission for ladies to their finals week bash. The fraternity made $75
lisabon 2012 [21]
<span>20 tickets for guys @ $2 = $40
35 tickets for gals @ $1 = $35
Total = 55 tickets and $75</span>
3 0
3 years ago
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