Answer:
import java.util.Scanner;
public class FindMatchValue {
public static void main (String [] args) {
final int NUM_VALS = 4;
int[] userValues = new int[NUM_VALS];
int i = 0;
int matchValue = 0;
int numMatches = -99; // Assign numMatches with 0 before your for loop
userValues[0] = 2;
userValues[1] = 2;
userValues[2] = 1;
userValues[3] = 2;
matchValue = 2;
numMatches=0;
for(i=0;i<NUM_VALS;i++)
{
if(userValues[i]==matchValue)//cheking if the array element is equal to match value.
{
numMatches++;
}
}
System.out.println(numMatches);//printing the matchvalue.
}
}
Output:-
3
Explanation:
First I have set the value numMatches to 0 before the loop.Then I have user the for loop to iterate over the array.In the for loop I am checking that the array element is equal to the matchValue or not if it is equal then increasing the numMatches by 1.Then at last print the value of numMatches.
D)Animated abstract shapes
There are two ways to convert from hexadecimal to denary gcse method. They are:
- Conversion from hex to denary via binary.
- The use of base 16 place-value columns.
<h3>How is the conversion done?</h3>
In Conversion from hex to denary via binary:
One has to Separate the hex digits to be able to know or find its equivalent in binary, and then the person will then put them back together.
Example - Find out the denary value of hex value 2D.
It will be:
2 = 0010
D = 1101
Put them them together and then you will have:
00101101
Which is known to be:
0 *128 + 0 * 64 + 1 *32 + 0 * 16 + 1 *8 + 1 *4 + 0 *2 + 1 *1
= 45 in denary form.
Learn more about hexadecimal from
brainly.com/question/11109762
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Http://www.cprogramming.com/tutorial/string.html
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The answer is <span>Digital data
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